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Elemente de algebra liniara.pdf

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156 <strong>Elemente</strong> <strong>de</strong> algebră liniară<br />

are raza <strong>de</strong> convergent¸ă r = ∞ rezultă că pentru orice matrice A ∈ Mn×n(K) putem<br />

<strong>de</strong>fini matricea<br />

e A =<br />

∞<br />

k=0<br />

A k<br />

k!<br />

A A2<br />

= 1 + + + · · ·<br />

1! 2!<br />

numită exponent¸iala matricei A. Se poate arăta că funct¸ia matriceală<br />

este <strong>de</strong>rivabilă ¸si că (e tA ) ′ = A e tA adică<br />

R −→ Mn×n(K) : t ↦→ e tA<br />

Y (t) = e tA C<br />

este solut¸ie a sistemului liniar Y ′ = AY , oricare ar fi C ∈ R n .<br />

Exercit¸iul 7.6 Să se <strong>de</strong>termine solut¸ia sistemului<br />

Rezolvare. Matricea sistemului<br />

este diagonalizabilă<br />

⎛<br />

Deoarece<br />

obt¸inem<br />

S −1 AS =<br />

⎛<br />

A k ⎜<br />

= S ⎝<br />

⎜<br />

⎝<br />

⎧<br />

⎪⎨<br />

⎪⎩<br />

2 0 0<br />

0 −1 0<br />

0 0 −1<br />

A =<br />

y ′ 1 = y2 + y3<br />

y ′ 2 = y1 + y3<br />

y ′ 3 = y1 + y2.<br />

⎞<br />

⎜<br />

A = S ⎝<br />

2 0 0<br />

0 −1 0<br />

0 0 −1<br />

⎛<br />

⎜<br />

⎝<br />

0 1 1<br />

1 0 1<br />

1 1 0<br />

⎞<br />

⎟<br />

⎠<br />

⎟<br />

⎠ un<strong>de</strong> S =<br />

⎛<br />

⎞k<br />

⎟<br />

⎠<br />

2 0 0<br />

0 −1 0<br />

0 0 −1<br />

⎛<br />

S −1 ⎜<br />

= S ⎝<br />

⎞<br />

⎟<br />

⎠ S −1<br />

⎛<br />

⎜<br />

⎝<br />

1 1 0<br />

1 0 1<br />

1 −1 −1<br />

2 k 0 0<br />

0 (−1) k 0<br />

0 0 (−1) k<br />

⎞<br />

⎞<br />

⎟<br />

⎠ .<br />

⎟<br />

⎠ S −1

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