Phylogénie Et Evolution Du Comportement Social Chez Les Blattes ...

ablesAn n e x e sTable 4Partitioned Bremer support values. Nodes correspond to the nodes numbers figuring on thefigure 3. “∑” is the total Bremer support for each gene and “%” is the percentage of Bremervalues that each gene supports normalized by the number of parsimony informative charactersas provided by PAUP 4.0b10 (data not shown). Then, for each gene i,% i = ((∑ i /∑ TOT *100)/N i )*100; with N i the number of informative character for the gene i.Char. / Nodes 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 2612S 25 22 2 4 0 3 6 14 9 0 3 0 0 25 2.3 2 -3 0 -9 0 0 -2 6 12 7 2816S 24 16 9 3 17 5 4 11 14 10 -1 7 9 0 9 5 6 2 -3 2 6 -3 6 0 0 018S 13 1 6 4 7 5 -5 27 4 3 -1 23 14 8 -1 1 0 0 0 0 0 0 -1 4 -1 228S 8 12 5 10 34 25 -2 1 50 7 4 5 20 31 6.5 4 0.5 0 2 0 0 2 -3 13 -2 9COI 22 -5 8 11 0 2 6 4 -3 3 -3 7 -9 0 -4 -3 1 0 3 0 0 4 9 0 0 0COII 12 -2 18 -1 0 0 -9 1 -6 0 0 -7 13 -12 13 2 11.5 1 10 -1 5 4 2 -5 0 0CYTB 0 0 0 3 0 3 7 0 7 0 2 6 8 0 1 3 3 5 5 3 -4 0 3 1 2 24TOT 104 44 48 34 58 43 7 58 75 23 4 41 55 52 27 14 19 8 8 4 7 5 22 25 6 63Table 4 (cont.)27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 ∑ %7 24 17 0 0 10 3 13 15 38 0 3 -1 11 2 3 6 6 0 0 0 0 -7 0 10 316.3 80 5 15 9 6 0 0 0 7 0 5 0 0 0 7 0 0 0 7 1 3 5.5 8 2 0 238.5 5.61 9 3 7 0 0 0 0 -2 0 2 0 0 0 2 0 -0.5 -6 0 0 1 0 -1 1 -1 128.5 5.2-2 10 4 0 0 0 0 0 7 0 1 0 0 0 4 2 2 6 0 2 2 2 4 4 5 295 2.90 15 -1 0 0 3 6 12 2 12 0 5 5 5 -1 6 0.5 9 0 -5 5 13 35 -1 -1 177.5 2.53 0 0 29 9 0 0 0 -3 0 4 0 0 0 1 0 0 0 0 4 -3 5.5 25 -1 0 123 2.12 10 5 0 0 0 0 0 -4 0 1 0 0 0 2 0 0 0 0 2 0 0 2 0 0 102 4.711 73 43 45 15 13 9 25 22 50 13 8 4 16 17 11 8 15 7 4 8 26 66 5 13 1381375