05.04.2016 Views

Modern Engineering Thermodynamics

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

122 CHAPTER 4: The First Law of <strong>Thermodynamics</strong> and Energy Transport Mechanisms<br />

EXAMPLE 4.10<br />

The magnetic susceptibility of the diamond in the gold engagement ring shown in<br />

Figure 4.17 is −2.20 × 10 −5 at 20.0°C. Determine the (a) total magnetic and (b) material<br />

magnetic work required to change the magnetic field of a 1 carat diamond having a<br />

volume of 5.00 × 10 −6 m 3 from 0.00 to 1.00 × 10 3 A/m.<br />

Solution<br />

a. The total magnetic work required is given by Eq. (4.62) as<br />

<br />

ð1W 2 Þ magnetic<br />

= − μ 0 Vð1 + χ m Þ H2 2 − <br />

H2 1<br />

2<br />

FIGURE 4.17<br />

Example 4.10.<br />

a) W total magnetic = ?<br />

b) W material magnetic = ?<br />

1 carat diamond<br />

where μ 0 = 4π × 10 −7 V·s/A·m and χ m = −2.20 × 10 −5 . Then,<br />

ð1W 2<br />

<br />

Þ magnetic = − 4π × 10 −7 V ⋅ s<br />

ð5:00 × 10 − 6 m 3 Þð1 − 2:20 × 10 −5 Þ 1:00 × 106 − 0A 2 /m 2 <br />

A ⋅ m<br />

2<br />

= −3:14 × 10 − 6 J<br />

b. The magnetic work required to change the magnetic field strength inside the diamond alone is given by Eq. (4.63) as<br />

and, using the values from part a, we get<br />

<br />

2 W 2<br />

<br />

H2 2 ð1W 2 Þ materia1<br />

= − μ 0 Vχ − <br />

H2 1<br />

m<br />

2<br />

magnetization<br />

<br />

<br />

<br />

= − 4π × 10 − 7 V ⋅ s<br />

ð5:00 × 10 − 6 m 3 Þð−2:20 × 10 − 5 Þ 1:00 × 106 − 0A 2 /m 2 <br />

magnetic A ⋅ m<br />

2<br />

= 6:91 × 10 − 11 J<br />

Exercises<br />

22. The magnetic susceptibility of gold is −3.60 × 10 −5 . If the gold in the ring of Example 4.10 has a volume of 1.00 × 10 −5 m 3 ,<br />

determine the total magnetic work required to change the magnetic field strength of the ring (the gold plus the diamond)<br />

from 0 to 1.00 × 10 3 A/m. Answer: ( 1 W 2 ) magnetic = −9.42 × 10 −6 J.<br />

23. The magnetic susceptibility of a ferromagnetic material such as iron varies with the applied magnetic field. However, if we<br />

assume it is constant over a small range of field strength at a value of 1800, then determine the (a) total work and (b) the<br />

material work required to magnetize a rectangular iron bar 0.500 inches square by 6.00 inches long from an initial magnetic<br />

field strength of zero to a magnetic field strength of 100. A/m. Answer: ( 1 W 2 ) total = ( 1 W 2 ) iron = −2.78 × 10 −4 J.<br />

4.7.4 Chemical Work<br />

Chemical work occurs whenever a specific chemical species is added to or removed from a system. Here, the<br />

generalized force is the intensive property μ i , the Gibbs chemical potential of chemical species i, and the generalized<br />

displacement is the extensive property m i , the mass of the chemical species added or removed. 8 Since any<br />

number of chemical species may be involved in a process, we write the chemical work as the sum over all k of<br />

the i species that are moved from the system to the surroundings as<br />

and so<br />

ðdWÞ chemical = −∑ k<br />

i=1<br />

μ i dm i (4.64)<br />

Z 2<br />

ð 1<br />

W 2 Þ chemical<br />

= −<br />

1<br />

∑ k<br />

i=1<br />

μ i dm i (4.65)<br />

8 In chemistry texts, the chemical potential is usually defined on a molar (i.e., per unit gram mole) basis. In this text, we define it as a<br />

standard intensive (per unit mass) property.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!