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Modern Engineering Thermodynamics

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12.9 Mixtures of Real Gases 431<br />

When p, v, T, andc v data on the gas mixture of interest are not available, engineering approximations can be<br />

obtained by combining either Dalton’s orAmagat’s law with the simplified compressibility factor equation of<br />

state pV = ZmRT. For example, using Dalton’s law,<br />

p m = ∑ N<br />

where p Di is the Dalton compressibility factor partial pressure, defined by<br />

i=1<br />

p Di = Z Dm m m R m T m /Vm (12.35)<br />

p Di = Z Di m i R i T m /V m<br />

and Z Di and Z Dm are the Dalton species i and mixture compressibility factors, respectively. Substituting the latter<br />

equation into the former and solving for Z Dm gives<br />

Dalton compressibility factor<br />

Z Dm = ∑ N<br />

i=1<br />

<br />

w i M m<br />

Z di = ∑ N<br />

M i<br />

i=1<br />

χ i Z Di (12.36)<br />

For each gas i, the Dalton Z Di compressibility factor is determined from the compressibility charts (Figures 7.5, 7.6,<br />

and 7.9 in Chapter 7) by using the reduced temperature T Ri and reduced pseudospecific volume v′ Ri for gas i at the<br />

temperature and volume of the mixture, or<br />

T Ri = T m /T ci<br />

v′ Ri = v Di p ci /ðR i T ci Þ<br />

= ðV m /m i Þðm m /m m Þðp ci Þ/ðR i T ci Þ = ðv m /w i Þ½p ci /ðR i T ci ÞŠ<br />

= ðV m /n i Þðn m /n m Þðp ci Þ/ðRT ci Þ = ðv m /x i Þ½p ci /ðRT ci ÞŠ<br />

where v Di = V m /m i = v m /w i is the Dalton specific volume of gas i, and v m = V m /m m and v m = V m /n m are the mixture<br />

mass and molar specific volumes, respectively. Notethatwecannotusethereducedpressurep Ri = p Di /p ci in this<br />

case because p Di = Z Di m i R i T m /V m , and Z Di is not usually known in advance.<br />

EXAMPLE 12.14<br />

A new type of fuel for the camping stove shown in Figure 12.12 is made by mixing 3.00 lbm<br />

of methane (CH 4 ) with 4.00 lbm of propane (C 3 H 8 ) and compressing the mixture into a<br />

1.00 ft 3 portable storage tank. Use the Dalton compressibility factor to determine the total<br />

pressure in the tank when it is exposed to the hot summer sun and its internal temperature<br />

reaches 240.°F.<br />

Solution<br />

The unknown is the total pressure in the tank. Here, we use Eq. (12.35) to determine the<br />

mixture pressure as<br />

p m = Z Dmm m R m T m<br />

V m<br />

where Z Dm is the Dalton compressibility factor, determined from Eq. (12.36) as<br />

Z Dm = ∑ N<br />

i=1<br />

<br />

w i M m<br />

M i<br />

First, we find the mixture composition and molecular mass. The mass of the entire mixture<br />

is m m = m methane + m propane = 3.00 + 4.00 = 7.00 lbm. The mass fractions are<br />

Z Di<br />

w methane = 3:00=7:00 = 0:429<br />

w propane = 4:00=7:00 = 0:571<br />

FIGURE 12.12<br />

Example 12.14.<br />

(Continued )

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