05.04.2016 Views

Modern Engineering Thermodynamics

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

10 CHAPTER 1: The Beginning<br />

EXAMPLE 1.2 (Continued )<br />

Solution<br />

(a) From Table 1.1, we find that both 0°N and 32°F correspond to the freezing point of water, and body heat (temperature)<br />

corresponds to 12°N and 98.6°F (on the modern Fahrenheit scale) on these scales. Since both these scales are linear<br />

temperature scales, we can construct a simple proportional relation between the two scales as<br />

98:6 − 55<br />

98:6 − 32 = 12 − x<br />

12 − 0<br />

where x is the temperature on the Newton scale that corresponds to 55°F. Solving for x gives<br />

<br />

<br />

98:6 − 55<br />

x = 12 1 − = 4:14°N⁡<br />

98:6 − 32<br />

(b) Since the Reaumur scale is also a linear scale with 0°Re and 80°Re corresponding to 32°F and 212°F, respectively, we<br />

can establish the following proportion for the Reaumur temperature y that corresponds to 55°F:<br />

from which we can solve for<br />

212 − 55<br />

212 − 32 = 80 − y<br />

80 − 0<br />

<br />

<br />

212 − 55<br />

y = 80 1 −<br />

212 − 32<br />

= 10:2°Re⁡<br />

(c) Here we have 273.15 K and 373.15 K corresponding to 32°F and 212°F, respectively. The proportionality between these<br />

scales is then<br />

212 − 55<br />

212 − 32 = 373:15 − z<br />

373:15 − 273:15<br />

from which we can compute the Kelvin temperature z that corresponds to 55°F as<br />

<br />

212 − 55<br />

z = 373:15 − ð373:15 − 273:15Þ = 285:9K⁡<br />

212 − 32<br />

Notice that we do not use the degree symbol (°) with either the Kelvin or the Rankine absolute temperature scale symbols.<br />

The reason for this is by international agreement as explained later in this chapter.<br />

Exercises<br />

4. Convert 20.0°C into Kelvin and Rankine. Answer: 293.2 K and 527.7 R.<br />

5. Convert 30°C into degrees Newton and degrees Reaumur. Answer: 9.7°N and 24°Re.<br />

6. Convert 500. K into Rankine, degrees Celsius, and degrees Fahrenheit. Answer: 900 R, 226.9°C, and 440.3°F.<br />

1.7 CLASSICAL MECHANICAL AND ELECTRICAL UNITS SYSTEMS<br />

The establishment of a stable system of units requires the identification of certain measures that must be taken<br />

as absolutely fundamental and indefinable. For example, one cannot define length, time, or mass in terms of<br />

more fundamental dimensions. They all seem to be fundamental quantities. Since we have so many quantities<br />

that can be taken as fundamental, we have no single unique system of units. Instead, there are many equivalent<br />

units systems, built on different fundamental dimensions. However, all the existing units systems today have<br />

one thing in common—they have all been developed from the same set of fundamental equations of physics,<br />

equations more or less arbitrarily chosen for this task.<br />

It turns out that all the equations of physics are mere proportionalities into which one must always introduce a<br />

“constant of proportionality” to obtain an equality. These proportionality constants are intimately related to the<br />

system of units used in producing the numerical calculations. Consequently, three basic decisions must be made<br />

in establishing a consistent system of units:<br />

1. The choice of the fundamental quantities on which the system of units is to be based.<br />

2. The choice of the fundamental equations that serve to define the secondary quantities of the system of units.<br />

3. The choice of the magnitude and dimensions of the inherent constants of proportionality that appear in the<br />

fundamental equations.<br />

With this degree of flexibility, it is easy to see why such a large number of measurement units systems have<br />

evolved throughout history.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!