05.04.2016 Views

Modern Engineering Thermodynamics

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

192 CHAPTER 6: First Law Open System Applications<br />

EXAMPLE 6.7 (Continued )<br />

Filling<br />

valve<br />

High-pressure liquid<br />

water at 20.0°C and<br />

50.0 MPa<br />

Initially empty rigid<br />

insulated tank<br />

FIGURE 6.15<br />

Example 6.7.<br />

The unknown is the final temperature in the tank. The material is liquid water.<br />

The final temperature in the tank immediately after it has been filled is given by Eq. (6.35) as<br />

T final filled = T in + vp in<br />

c<br />

In this problem T in =20.0°C, p in = 50.0 MPa, and the specific heat of liquid water can be found in Table 3.5 as c = 4.216 kJ/kg·K.<br />

Even though the pressure range is quite high here (0 to 50.0 MPa), it is still a good assumption to take the specific volume of<br />

the water to be a constant at the value of v f (20.0°C) = 0.001002 m 3 /kg; the value of v (20.0°C, 50.0 MPa) from Table C.4b of<br />

Thermodynamic Tables to accompany <strong>Modern</strong> <strong>Engineering</strong> <strong>Thermodynamics</strong> is 0.0009804 m 3 /kg, which is approximately the same<br />

as v f (20.0°C). Then, Eq. (6.35) gives<br />

T final filled = 20:0°C + ð0:001002 m3 /kgÞð50:0 × 10 3 kN/m 2 Þ<br />

4:216 kN.m/kg.K<br />

= 31:9°C<br />

Exercises<br />

18. An insulated, initially empty rigid container is filled with water from a water faucet in a house to a pressure of 0.700<br />

MPa. The temperature of the water in the faucet and entering the container is 20.0°C. Determine the final temperature in<br />

the container immediately after it has been filled. Answer: T filled = 20.2°C.<br />

19. Determine the final temperature in the tank in Example 6.7 if it is filled with liquid mercury instead of water under the<br />

same conditions. Use v = 7.50 × 10 −5 m 3 /kg for mercury. Answer: T filled = 20.9°C.<br />

On the other hand, if we assume that the tank is filled with an ideal gas, then we can utilize Eq. (6.22) to get<br />

u 2 = c v T 2 = h in = c p T in<br />

or<br />

T 2<br />

<br />

filling<br />

ideal<br />

gas<br />

= c p /c v<br />

<br />

Tin = kT in (6.36)<br />

In the case of an ideal gas, the compression process generates a considerable amount of internal energy, as the<br />

following example illustrates.<br />

EXAMPLE 6.8<br />

A scuba diving air tank is filled from a 20.0°C, 1.40 MPa air supply. Neglecting the effect of any air initially in the tank and<br />

assuming the tank is insulated during the filling process, determine the final temperature of the air in the tank immediately<br />

after it is filled.<br />

Solution<br />

First, draw a sketch of the system (Figure 6.16).

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!