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Modern Engineering Thermodynamics

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334 CHAPTER 10: Availability Analysis<br />

10.9 OPEN SYSTEM AVAILABILITY RATE BALANCE<br />

The open system availability rate balance is obtained from the closed system availability rate balance simply by<br />

adding the flow availability resulting from all the inlet and outlet flow streams to Eq. (10.17) to yield the open<br />

system availability rate balance (ARB):<br />

∑ n<br />

i=1<br />

<br />

1 − T <br />

0<br />

T bi<br />

Open system availability rate balance<br />

<br />

_ma f + p 0<br />

_V − _I =<br />

_Q i − _W +∑ _ma f − ∑<br />

inlet outlet<br />

dA<br />

dt<br />

<br />

system<br />

(10.21)<br />

As in the case of the open system energy rate balance, several specific cases merit special consideration. These<br />

cases are described in detail next.<br />

■ Case 1 Steady State<br />

A steady state is reached when all system properties are independent of time, then d(any system property)/dt = 0.<br />

Thus, at a steady state, we have<br />

dA<br />

dt<br />

= d h<br />

i<br />

E − E 0 + p 0 ðV − V 0Þ − T 0 ðS − S 0 Þ<br />

dt<br />

= 0<br />

system<br />

and, since E 0 , p 0 , V 0, T 0 , and S 0 are all constants, this reduces to<br />

dA<br />

dt<br />

<br />

= dE<br />

dt + p dV<br />

0<br />

dt − T dS <br />

0 = 0<br />

dt system<br />

But since E, V, and S are also system properties, their individual time derivatives must also vanish, so that, in<br />

a steady state, we must have the following system conditions:<br />

Steady state means:<br />

dA<br />

dt<br />

= dE<br />

dt<br />

= dV<br />

dt<br />

= dS<br />

dt = 0 (10.22)<br />

■<br />

■ Case 2 Steady Flow<br />

Equation (6.22) defines steady flow as<br />

∑<br />

inlet<br />

_m = ∑<br />

outlet<br />

_m<br />

so that there is no accumulation or depletion of mass within the system during steady flow.<br />

■<br />

■ Case 3 Single Inlet, Single Outlet<br />

In an open system with a single inlet and a single outlet, the summation signs on the flow availability terms<br />

can be dropped. Then,<br />

∑ _ma f − ∑ _ma f = ð _ma f Þ inlet − ð _ma f Þ outlet (10.23)<br />

inlet outlet<br />

If the system is also at a steady flow, then Eq. (10.22) tells us that _m inlet = _m outlet , and the flow availability<br />

terms for a steady flow system with a single inlet and single outlet can then be written as<br />

∑ _ma f − ∑ _ma f = _m½ða f Þ inlet<br />

− ða f Þ outlet<br />

Š (10.24)<br />

inlet outlet<br />

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