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Modern Engineering Thermodynamics

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538 CHAPTER 14: Vapor and Gas Refrigeration Cycles<br />

EXAMPLE 14.1<br />

A new die-casting operation has a large amount of waste heat available at 200.°C in a location where the local environmental<br />

temperature is 20.0°C. As chief engineer in charge of thermal energy management, investigate the possibility of recovering<br />

some of this waste heat by determining<br />

a. The thermal efficiency of a Carnot engine operating between these temperatures.<br />

b. The coefficient of performance of a Carnot heat pump operating between these temperatures.<br />

c. The coefficient of performance of a Carnot refrigerator or air conditioner operating between these temperatures.<br />

Solution<br />

First, draw a sketch of the system (Figure 14.2).<br />

Die-casting<br />

machine<br />

at 200.°C<br />

Die-casting<br />

machine<br />

at 200.°C<br />

Die-casting<br />

machine<br />

at 200.°C<br />

Waste heat Heat out Waste heat<br />

Carnot<br />

heat<br />

engine<br />

Carnot<br />

Carnot<br />

refrigerator<br />

Work heat Work Work<br />

or air<br />

pump<br />

conditioner<br />

Heat out Heat in Heat out<br />

Environment<br />

at 20.0°C<br />

Environment<br />

at 20.0°C<br />

Environment<br />

at 20.0°C<br />

(a) (b) (c)<br />

FIGURE 14.2<br />

Example 14.1.<br />

a. Equation (13.2) gives the thermal efficiency of a Carnot engine operating between the temperature limits of 200. +<br />

273.15 = 473.15 K and 20.0 + 273.15 = 293.15 K as<br />

ðη T Þ Carnot = 1 − T L<br />

= 1 − 293:15 K = 0:380 = 38:0%<br />

T H 473:15 K<br />

b. Equation (14.4) gives the coefficient of performance of the same Carnot engine running backward as a heat pump as<br />

COP Carnot HP =<br />

T H 473:15 K<br />

=<br />

T H − T L 473:15 − 293:15 K = 2:63<br />

c. Equation (14.5) gives the coefficient of performance of the same Carnot engine running backward as a refrigerator or air<br />

conditioner as<br />

COP Carnot R/AC =<br />

T L<br />

=<br />

293:15 K<br />

T H − T L 473:15 − 293:15 K = 1:63<br />

Note that the COP Carnot HP = COP Carnot R/AC + 1 as Eq. (14.1) requires, and that Eqs. (14.2) and (14.3) are also<br />

satisfied here.<br />

Thermal energy management is a serious problem in the industrial environment. Lost thermal energy often reflects poor process<br />

design and lost money. It can be remedied by considering the waste heat as an energy source and applying a technology that can<br />

utilize it in some fashion.<br />

Exercises<br />

1. Suppose the waste heat in Example 14.1 is available at 35.0°C instead of 200.°C while the environmental temperature<br />

remains at 20.0°C. Determine the thermal efficiency of a Carnot engine operating between these temperatures and the<br />

coefficient of performance of a Carnot air conditioning unit. Answer: (η T ) Carnot = 4.90%, and COP Carnot AC = 20.5.<br />

2. During winter, the environmental temperature in the die-casting facility in Example 14.1 drops to 0.00°C. Recompute<br />

the thermal efficiency and coefficient of performance, assuming the waste heat temperature remains at 200.°C. Answer:<br />

(η T ) Carnot = 42.3%, COP Carnot HP = 2.37, and COP Carnot R/AC = 1.37.

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