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Modern Engineering Thermodynamics

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190 CHAPTER 6: First Law Open System Applications<br />

EXAMPLE 6.6 (Continued )<br />

The MERB for the conditions described in the problem statement is Eq. (6.31):<br />

_W shaft = _mðh 1 − h 2 Þ<br />

We do not know _m here, but we do know the energy produced per kilogram of steam flowing:<br />

W/m = _W/ _m = 2000: kJ/kg, so 2000: kJ/kg = h 1 − h 2<br />

m<br />

1<br />

2<br />

Unknown: x 2 = ?<br />

W/m = 2000. kJ/kg<br />

Station 1<br />

p 1 = 2.00 MPa<br />

T 1 = 800.°C<br />

h 1 = 4150.4 kJ/kg<br />

Process: Turbine<br />

Station 2<br />

p 2 = 1.00 kPa<br />

h 2 = 2150.4 kJ/kg<br />

x 2 = ?<br />

FIGURE 6.13<br />

Example 6.6.<br />

From Table C.3b of Thermodynamic Tables to accompany <strong>Modern</strong> <strong>Engineering</strong> <strong>Thermodynamics</strong>, wehaveh 1 = 4150:4 kJ/kg; and<br />

from Table C.2b, we have h f 2 = 29:30 kJ/kg, h fg2 = 2484:9 kJ/kg, and h g2 = 2514:2 kJ/kg (all at 1.0 kPa). Therefore,<br />

h 2 = h 1 − _W/ _m = 4150:4 − 2000: = 2150: kJ/kg<br />

These values of h 1 and h 2 have been added to our station data list in Figure 6.13. Hence, the values of h 2 = 2150: kJ/kg and<br />

p 2 = 1:00 kPa are a pair of independent properties in the outlet state. Therefore, the outlet quality can be found from the<br />

auxiliary formula for quality:<br />

<br />

<br />

x 2 = h 2 − h f 2 ð1:00 kPaÞ<br />

/hfg2 ð1:00 kPaÞ = ð2150: − 29:30Þ/2484:9 = 0:854<br />

= 85:4% vapor at the turbine’s outlet<br />

Exercises<br />

15. Determine the exit steam quality in Example 6.6 if the exit pressure is atmospheric pressure (0.101 MPa) instead of<br />

1.00 kPa and everything else remains the same. Answer: x 2 = 76.8%.<br />

16. Determine the exit steam quality in Example 6.6 if the inlet steam temperature is 900.°C instead of 800.°C and<br />

everything else remains the same. Answer: x 2 = 95.1%.<br />

17. Suppose the shaft power produced by the turbine in Example 6.6 is 2000. kW and the steam mass flow rate is 2.00 kg/s.<br />

Determine the exit steam quality if everything else remains the same. Answer: Since h 2 > h g (1 kPa) here, the exit steam<br />

is superheated and quality is not a valid property.<br />

6.10 OPEN SYSTEM UNSTEADY<br />

STATE PROCESSES<br />

There are a wide variety of open system unsteady state<br />

processes in industry. Most are too complex to analyze<br />

easily, but one of the simpler cases involves the filling<br />

or emptying of a rigid tank or vessel.<br />

Consider the tank-filling process illustrated in Figure<br />

6.14. In this system, a rigid tank is connected through<br />

a valve to a high-pressure supply pipe. When the valve<br />

is opened, the rigid tank is filled from the supply pipe<br />

until the tank pressure is equal to that of the supply<br />

pipe. This is the filling process that we analyze.<br />

The filling process is neither steady state nor steady flow,<br />

since the mass of the system is continually changing.<br />

FIGURE 6.14<br />

Filling a rigid vessel.<br />

High-pressure pipe<br />

Valve<br />

Rigid tank (vessel)<br />

System boundary

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