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Modern Engineering Thermodynamics

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6.6 Throttling Devices 179<br />

These assumptions imply a negligible aerodynamic drag on the water stream and negligible viscous dissipation within the<br />

stream itself. When these conditions are applied to the modified energy rate balance for system b, we obtain<br />

_Q ↘0<br />

− _W ↘0<br />

+ _m½h in − h out + ðV 2 in − 0Þ/2g c + ð0 − Z out Þg/g c Š b = 0<br />

or<br />

ðZ out Þ b = ½ðg c /gÞðh in − h out Þ + V 2 in /2gŠ b<br />

The change in specific enthalpy for this example is again given by Eq. (6.19), and under the assumptions listed for system b,<br />

it is clear that this change is zero. Then, our working modified energy rate balance reduces to<br />

or<br />

ðZ out Þ b =<br />

ðZ out Þ b = ðV 2 in Þ b/2g<br />

ð109 ft/sÞ 2<br />

2ð32:174 ft/s 2 = 185 ft<br />

Þ<br />

Note that our calculations for both (V out ) a<br />

and (Z out ) b in this example gave numbers somewhat higher than we would<br />

observe if we measured these values in an experiment. This is because we ignore the viscous dissipation effects in the water<br />

and surrounding air. Dissipation effects are considered in more detail in the next chapter, on the second law of<br />

thermodynamics.<br />

Exercises<br />

4. Determine the exit diameter of the garden hose nozzle used in Example 6.2. Assume the water is incompressible so that<br />

v in = v out . Answer: (D out ) a = 0.147 in.<br />

5. Determine the height to which the stream of water rises when the garden hose in Example 6.2 is pointed straight up and<br />

the nozzle removed. Answer: (Z out ) b = 1.03 in.<br />

6. If the exit diameter of the garden hose nozzle used in Example 6.2 is reduced to 0.100 in, determine the exit velocity and<br />

the height to which the stream of water rises when pointed straight up. Answers: (V out ) a = 235 ft/s, and (Z out ) b = 858 ft.<br />

6.6 THROTTLING DEVICES<br />

Throttling device is the generic name of any device or process that simply dissipates pressure energy _mpv by<br />

irreversibly converting it into thermal energy. Unlike nozzles and diffusers, throttling devices provide no form of<br />

useful energy recovery. They merely convert pressure energy into thermal energy through dissipative viscous flow<br />

(usually turbulent) processes. In fact, any device that incurs a large irreversible pressure drop can be thought of<br />

as a throttling device. Figure 6.5 schematically illustrates a variety of common throttling devices.<br />

p 1 p 2 < p 1 p 1<br />

p 2 < p 1<br />

(a) Orifice plate<br />

(b) Porous plug<br />

p 1 p 2 < p 1 p 1<br />

p 2 < p 1<br />

(c) Butterfly valve<br />

(d) Any type of flow or<br />

pressure control valve<br />

FIGURE 6.5<br />

Some common throttling devices.

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