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Modern Engineering Thermodynamics

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274 CHAPTER 8: Second Law Closed System Applications<br />

However, most systems of engineering interest do not undergo reversible processes, and the entropy produced<br />

by the irreversiblilties inherent in the system is of great value in the design process. Both the direct method and<br />

the indirect method can be used to find values for the entropy produced in any irreversible process. The indirect<br />

method is used in several examples developed in this chapter to determine the entropy produced by heating a<br />

fluid in a simple closed container, a lightbulb, a food blender, a typical electrical power plant, and so forth. The<br />

more complex direct method is then used to determine the entropy produced by convective heat transfer from a<br />

cooling fin, the viscosity of the lubricant liquid in an engine bearing, the electrical resistance of a circuit board,<br />

and the diffusional mixing of identical fluids.<br />

Problems (* indicate problems in SI units)<br />

1.* Air contained in a cylinder fitted with a piston initially at<br />

2.00 MPa and 2000.°C expands to 0.200 MPa in an isentropic<br />

process. Assuming the air behaves as a constant specific heat<br />

ideal gas, determine the following:<br />

a. The final temperature.<br />

b. The change in specific internal energy.<br />

c. The change in specific enthalpy.<br />

d. The change in specific entropy.<br />

e. The work done per lbm of air during the expansion.<br />

2. A constant specific heat ideal gas has a gas constant of 42.92 ft ·<br />

lbf/(lbm· R) and a constant pressure specific heat of 0.200Btu/<br />

(lbm· R). Determine the heat transferred and the change of total<br />

entropy if 9.00 lbm of this gas is heated from 40.0°F to 340.°F<br />

in a rigid container.<br />

3. A reversible Carnot heat engine has 1.00 lbm of air as the<br />

working fluid. Heat is received at 740.°F and rejected at 40.0°F.<br />

At the beginning of the heat addition process, the pressure is<br />

100. psia and during this process the volume triples. Calculate<br />

the net cycle work per lbm of air. Assume the air behaves as a<br />

constant specific heat ideal gas.<br />

4. A 1.000 ft 3 glass bottle is initially evacuated then has 1.000 g of<br />

water added that eventually comes to equilibrium at 70.00°F. The<br />

pressure in the bottle is increased by 11.1668 psia during a<br />

reversible adiabatic compression:<br />

a. What is the work done during compression?<br />

b. What is the entropy production for the compression?<br />

5. 3.00 lbm of Refrigerant-134a (not an ideal gas) is compressed<br />

adiabatically in a closed piston-cylinder device from 5.00 psia,<br />

220.°F to 200. psia, 340.°F.<br />

a. Determine the work for this process.<br />

b. Show whether or not this process violates the second law of<br />

thermodynamics.<br />

6.* An engineer claims to be able to compress 0.100 kg of water<br />

vapor at 200.°C and 0.100 MPa in a piston-cylinder<br />

arrangement in an isothermal and adiabatic process. The<br />

engineer claims that the final volume is 6.10% of the initial<br />

volume. Determine<br />

a. The final temperature and pressure.<br />

b. The work required.<br />

c. Show whether the process is thermodynamically possible.<br />

7. An inventive engineer claims to have designed a<br />

mechanochemical, single-stroke closed system that compresses<br />

l0.0 lbm of air isothermally from 14.7 psia, 100.°F to 200. psia<br />

while inputting 500. Btu of mechanochemical compression<br />

work. Assuming constant specific heat ideal gas behavior,<br />

a. What heat transfer is required for this process to occur?<br />

b. Does this process violate the second law of thermodynamics?<br />

8.* Saturated liquid water at 8.58 MPa undergoes a reversible<br />

isothermal process in a cylinder until the pressure reaches<br />

0.100 MPa. Calculate the heat transfer and work per kg of water<br />

for this process. Show the process on a T-s diagram. Neglect any<br />

changes in kinetic and potential energies.<br />

9.* Air is compressed in a steady state reversible adiabatic process<br />

from 25.0°C and 0.150 MPa to 1.70 MPa. Determine the change<br />

of specific enthalpy in this process and find the density of the exit<br />

air. Assume the air behaves as an ideal gas with constant specific<br />

heats. Neglect any changes in kinetic and potential energies.<br />

10.* One cubic meter of hydrogen (a constant specific heat ideal gas)<br />

expands from an initial pressure of 0.500 MPa to a final<br />

pressure of 0.100 MPa. The gas temperature before expansion<br />

is 27.0°C.<br />

a. Determine the final temperature if the process is isentropic.<br />

b. Determine the final temperature if the process is polytropic<br />

with n=1.30.<br />

c. Calculate the heat transfer required for the polytropic case.<br />

11. 2.00 lbm of saturated water vapor at 247.1 psia undergoes a<br />

reversible isothermal expansion until the pressure reaches<br />

20.0 psia. Determine the heat transfer and the work done for<br />

this process. The system boundary temperature is the same as<br />

the process temperature.<br />

12. Consider a fixed mass of a constant specific heat ideal gas in a<br />

piston-cylinder device undergoing a compression process for<br />

which pV n = constant (a polytropic process). Show that the<br />

work done per unit mass of gas in such a process is given by<br />

(p 2 v 2 – p 1 v 1 )/(n – 1) if n ≠ 1. If the process is isentropic, show<br />

that this reduces to c v (T 2 – T 1 ).<br />

13.* 0.130 kg of a constant specific heat ideal gas is compressed in a<br />

closed system from 1.00 atm and 40.0°C to 11.39 atm in an<br />

isothermal process. For this gas, c p = 523 J/(kg·K), c v = 315 J/<br />

(kg·K), and R = 208 J/(kg·K). For this process, determine<br />

a. The work required.<br />

b. The resulting heat transfer.<br />

c. The amount of entropy produced.<br />

d. Explain whether this process violates the second law of<br />

thermodynamics.<br />

14. Show that a constant specific heat ideal gas undergoing a<br />

constant heat flux polytropic process (pv n = constant with n ≠ 1)<br />

has a limiting isothermal system boundary temperature<br />

corresponding to a reversible process given by<br />

ðT b Þ rev<br />

= T 2 − T 1<br />

lnðT 2 /T 1 Þ<br />

(Hint: Recall that 1 W 2 =mR(T 2 – T 1 )/(n – 1) for such a<br />

polytropic process with an ideal gas.)

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