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Modern Engineering Thermodynamics

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6.3 Conservation of Energy and Conservation of Mass Equations for Open Systems 171<br />

Note that the ke and pe terms in Example 6.1 amount respectively to only 0.14% and 0.0015% of the total mass flow<br />

energy. This is because the specific enthalpy of steam (and most vapors) usually has a large numerical value, while the specific<br />

kinetic and potential flow energies for most engineering problems usually have much smaller values when converted into<br />

the same units. 2<br />

2 Actually, because of the form of the first law of thermodynamics, we normally compare values of the change in enthalpy, Δh, with the changes in ke, Δke,<br />

and pe, Δpe. Here, too, we find that Δh usually dominates.<br />

6.3 CONSERVATION OF ENERGY AND CONSERVATION<br />

OF MASS EQUATIONS FOR OPEN SYSTEMS<br />

To obtain a general working formula for the first law of thermodynamics for open systems, we begin by constructing<br />

a general energy rate balance (ERB) equation for these systems. The general open system energy rate<br />

balance is given by Eq. (4.22) as<br />

_Q − _W + _E mass<br />

flow<br />

= _E G<br />

where the rate of gain of total system energy _E G is given by Eq. (4.9) as<br />

_E G = d <br />

U + m <br />

V 2 + mgZ/g c<br />

dt 2g c<br />

and the mass flow energy transports are given by Eq. (6.2) as<br />

where<br />

_E mass<br />

flow<br />

system<br />

= ∑ _mðh + ke + peÞ − ∑ _mðh + ke + peÞ<br />

inlet<br />

outlet<br />

ðkeÞ inlet = V2 inlet<br />

2g c<br />

and<br />

ðkeÞ outlet = V2 outlet<br />

2g c<br />

ðpeÞ inlet<br />

= gZ inlet<br />

g c<br />

ðpeÞ outlet = gZ outlet<br />

g c<br />

are the specific kinetic and potential energies of each inlet and outlet flow stream. Combining these equations<br />

gives the general energy rate balance (ERB) for open systems:<br />

General open system energy rate balance<br />

_Q − _W +∑<br />

inlet<br />

= d dt<br />

<br />

_mðh + V 2 /2g c + gZ/g c Þ − ∑ _m h+ V 2 /2g c + gZ/g c<br />

outlet<br />

U + mV 2 /2g c + mgZ/g c<br />

system<br />

(6.4)<br />

It must be remembered that the _Q and _W terms in this equation are the net heat and work transport rate terms; that is,<br />

_Q =<br />

∑<br />

all<br />

boundaries<br />

_Q and _W = ∑<br />

all<br />

boundaries<br />

_W (6.5)

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