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Modern Engineering Thermodynamics

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132 CHAPTER 4: The First Law of <strong>Thermodynamics</strong> and Energy Transport Mechanisms<br />

WHAT IS THE SECRET TO SOLVING THERMODYNAMICS PROBLEMS?<br />

The secret to solving thermodynamic problems is to do the analysis first and do the calculations last, not the other way around.<br />

The basic process for solving a thermodynamics problem is this:<br />

Begin by carefully reading the problem statement completely through.<br />

Step 1. Make a sketch of the system and put a dashed line around the system boundary.<br />

Step 2. Identify the unknown(s) and write them on your system sketch.<br />

Step 3. Identify the type of system (closed or open) you have.<br />

Step 4. Identify the process that connects the states or stations.<br />

Step 5. Write down the basic thermodynamic equations and any useful auxiliary equations.<br />

Step 6. Algebraically solve for the unknown(s).<br />

Step 7. Calculate the value(s) of the unknown(s).<br />

Step 8. Check all algebra, calculations, and units.<br />

The process is this:<br />

Sketch ! Unknowns ! System ! Process ! Equations ! Solve ! Calculate ! Check<br />

For example, if you have a closed system that is initially at 14.7 psia with a specific volume of 0.500 ft 3 /lbm and by some<br />

process it ends up at 200. psia at a quality of 90.0%, you should write this information on your work sheet in the following<br />

form (always be sure to include the units on these values):<br />

Process path<br />

State 1 ƒƒƒƒƒ! State 2<br />

p 1 = 14:7 psia p 2 = 200: psia<br />

v 1 = 0:500 ft 3 /lbm x 2 = 0:900<br />

For example, if you have a flow stream entering the system at station 1 with a temperature of 300.°C andapressureof<br />

1.00 MPa, and a flow stream exiting the system at station 2 with a specific volume of 26.3 m 3 /kg and a quality of 99.0%,<br />

you should write this information on your work sheet as (always be sure to include the units on these values):<br />

Process path<br />

Station 1<br />

ƒƒƒƒƒ! Station 2<br />

p 1 = 1:00 MPa v 2 = 26:3m 3 /kg<br />

T 1 = 300:°C x 2 = 0:990<br />

Here, too, we are trying to identify two independent property values at each station, because in simple systems, they fix the<br />

state of the material at that station.<br />

Notice that, for “simple” thermodynamic systems, we always are looking for the values of two independent<br />

properties in each state. These two property values fix (i.e., determine) the state and we can then find the values<br />

of any of the other properties needed at that state.<br />

Often a problem statement gives only one property value at a system state. In this case, the remaining independent<br />

property value at that state is usually given by the process path statement that indicates how that state was<br />

achieved (e.g., an isothermal process tells us that T 2 = T 1 ) or else it may be a problem unknown to be<br />

determined.<br />

If it is an open system, we are interested in any changes that occur in the system bulk properties of the system<br />

plus all the properties of the entering and exiting flow streams. Flow stream properties are referred to as monitoring<br />

station properties, to clearly separate them from bulk system properties.

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