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Modern Engineering Thermodynamics

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7.6 Heat Engines Running Backward 217<br />

IS THE EFFICIENCY OF HEAT PUMPS, AIR CONDITIONERS,<br />

AND REFRIGERATORS GREATER THAN 100%?<br />

If you look closely at the thermal efficiency equations for heat pumps, air conditioners, and refrigerators, you see that their<br />

efficiency is going to be more than 100%, because under normal operating conditions, the numerator in their efficiency equation<br />

is usually greater than the denominator. Consequently, their energy conversion efficiency is usually greater than 100%.<br />

How can that be—nothing should have an energy conversion efficiency greater then 100%. But, it is correct. This is simply<br />

due to the way in which the thermal efficiency formula (Eq. (4.70)) is structured:<br />

Energy conversion efficiency = η E =<br />

Desired energy result<br />

Required energy input<br />

(4.70)<br />

This makes a heat pump much more attractive for domestic heating than, say, a purely resistive electrical heater. Electrical heaters<br />

convert all their input electrical energy directly into thermal energy and therefore have energy conversion efficiencies of<br />

100%, whereas most heat pumps have energy conversion efficiencies far in excess of 100% for the same electrical energy input.<br />

Since this could be a problem in public advertising, the industry uses the phrase coefficient of performance (COP) instead of<br />

efficiency. The COP is simply the pure efficiency number before it is converted into a percentage. For example, the COP of<br />

a heat pump with an energy conversion efficiency of 450% is 4.5.<br />

COP heat<br />

= η heat<br />

= jQ Hj<br />

=<br />

jW<br />

pump pump in j<br />

jQ H j<br />

jQ H j − Q L<br />

=<br />

j _Q H j<br />

=<br />

j _W in j<br />

j _Q H j<br />

j _Q H j − _Q L<br />

(7.17)<br />

The desired energy result in the operation of a heat pump is heat addition to an already warm environment.<br />

Therefore, its energy conversion efficiency can be determined from Eq. (4.70) and an energy balance on the<br />

device (see Figure 7.9b) as<br />

η heat<br />

=<br />

pump<br />

Desired energy result<br />

Required energy input = jQ Hj<br />

jW in j<br />

=<br />

jQ H j<br />

jQ H j − Q L<br />

=<br />

j _Q H j<br />

j _W in j<br />

=<br />

j _Q H j<br />

j _Q H j − _Q L<br />

where, as in the previous section, we use the absolute values of certain terms to avoid improper or confusing<br />

algebraic signs.<br />

If the heat pump is modeled as a backward running Carnot heat engine, then Eqs. (7.15) and (7.17) can be<br />

combined to yield the COP for a “reversible” (i.e., frictionless, etc.), or Carnot, heat pump as<br />

COP Carnot<br />

=<br />

heat pump<br />

T H<br />

T H − T L<br />

(7.18)<br />

If the removal of heat Q L from a space is the desired result of a backward running heat engine, then the engine<br />

is called a refrigerator when food is stored in the cooled space and an air conditioner when people occupy the<br />

cooled space.<br />

The energy conversion efficiency of a refrigerator or air conditioner can also be obtained from Eq. (4.70). As in<br />

the case of a heat pump, these efficiencies are also normally greater than 100% and they too are commonly<br />

represented with the pure number coefficient of performance label<br />

COP refrig: or<br />

= η refrig: or<br />

=<br />

air cond: air cond:<br />

= Q L<br />

jW in j<br />

=<br />

Desired energy result<br />

Required energy input<br />

Q L<br />

jQ H j − Q L<br />

=<br />

_Q L<br />

j _W in j<br />

=<br />

(7.19)<br />

_Q L<br />

j _Q H j − _Q L<br />

For a backward running Carnot (i.e., reversible) heat engine, Eqs. (7.15) and (7.19) can be combined to give the<br />

COP for a reversible refrigerator or air conditioner as<br />

T<br />

COP Carnot = L<br />

(7.20)<br />

refrig: or<br />

T H − T L<br />

air cond:

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