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Modern Engineering Thermodynamics

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Problems 443<br />

exhaust gas is an ideal gas and ignore all kinetic and potential<br />

energy effects.<br />

29. An air–water vapor mixture at 14.7 psia, 100.°F, and 40.4%<br />

relative humidity is contained in a 10.0 ft 3 closed tank. The<br />

tank is cooled until the water just begins to condense.<br />

Determine the temperature at which condensation begins.<br />

30. When the dew point of atmospheric air is between 60.0°F and<br />

70.0°F, the weather is said to be humid, and when it is above<br />

70.0°F it is said to be tropical. If the partial pressure of water<br />

vapor in the air is 0.400 psia when the dry bulb temperature is<br />

80.0°F, determine the relative humidity and whether the weather<br />

is humid or tropical.<br />

31. The volume fractions of the gases in the atmosphere of Mars<br />

measured at the surface of the planet, where the total<br />

atmospheric pressure is 0.112 psia, were found by the early<br />

Viking I mission to be 95.0% CO 2 , 2.50% N 2 , 2.00% Ar,<br />

0.400% O 2 , and 0.100% H 2 O. Determine<br />

a. The partial pressure of the water vapor in the Martian<br />

atmosphere.<br />

b. The mass fractions of all the gases in the Martian<br />

atmosphere.<br />

c. The humidity ratio of the Martian atmosphere (consider the<br />

Martian dry “air” to be everything in its atmosphere except<br />

the water vapor).<br />

32. An engineer at a party is handed a cold glass of beverage with<br />

ice in it. The engineer estimates the outside temperature of the<br />

glass to be 35.0°F and the room temperature to be 70.0°F. What<br />

is the relative humidity in the room when moisture just begins<br />

to condense on the outside of the glass?<br />

33.* The list of cities in Table 12.6 includes representative wet and<br />

dry bulb temperatures. Use the psychrometric chart to determine<br />

their corresponding relative humidity, humidity ratio, dew point<br />

temperature, and water vapor partial pressure.<br />

34. People often clean eyeglasses by holding them near their mouths<br />

and exhaling heavily on them. This usually causes the lenses to<br />

“fog”; the moisture is then wiped off, and this process cleans the<br />

lenses. Assuming the air in the lungs has a relative humidity of<br />

75.0% at a dry bulb temperature of 100.°F, determine the<br />

maximum temperature of the glasses that just causes moisture<br />

droplets (i.e., “fog”) to form when cleaned in this manner.<br />

35.* 7000 m 3 /min of air at 28.0°C and 0.101 MPa with a relative<br />

humidity of 60.0% is to be cooled at constant total pressure to<br />

its dew point temperature. Determine the required heat transfer<br />

rate and indicate its direction.<br />

36. 30 ft 3 /min of air with a dry bulb temperature of 90.0°F and a<br />

relative humidity of 80.0% is to be cooled and dehumidified to<br />

a dry bulb temperature of 65.0°F and a relative humidity of<br />

50.0%. Determine (a) the wet bulb temperature of the air before<br />

dehumidification, (b) the dew point temperature of the air after<br />

dehumidification, (c) the amount of moisture removed during<br />

the dehumidification process, and (d) the amount of heat<br />

removed during the cooling part of the dehumidification<br />

process.<br />

37.* A room containing 275 m 3 of air at 1.00 atm pressure is to be<br />

humidified. The initial conditions are T DB = 24.0°C and<br />

ϕ = 20.0%, and the final conditions are T DB = 20.0°C and<br />

ϕ = 60.0%. Determine the mass of water that must be added to<br />

the room air.<br />

38. 1000. ft 3 /h of moist air at atmospheric pressure, 80.0°F and<br />

70.0% relative humidity is to be cooled to 50.0°F at constant<br />

total pressure. Find whether or not this can be done without the<br />

removal of water from the air. If it cannot, determine the<br />

minimum amount of water that must be removed in lbm/h.<br />

39. A classroom contains 6000. ft 3 of air–water vapor mixture at<br />

1.00 atm total pressure. The dry bulb temperature is 70.0°F and<br />

the wet bulb temperature is 65.0°F. Assuming a closed constant<br />

total pressure system, determine the following:<br />

a. The relative humidity.<br />

b. The partial pressure of the water vapor.<br />

c. The dew point.<br />

d. The amount of water that must be added to or removed<br />

from the air in the room to achieve 40.0% relative humidity<br />

at the same dry bulb temperature.<br />

40. 10,000. ft 3 /h of moist air at 14.7 psia and 75.0°F is to be cooled<br />

to 45.0°F at constant total pressure. Find the amount (lbm/h) of<br />

water condensed if the mole fraction of water in the inlet<br />

mixture is 0.0260.<br />

41.* Atmospheric air can be dehumidified by cooling the air at<br />

constant total pressure until the moisture condenses out.<br />

Suppose that air with a humidity ratio of 5.00 × 10 −3 kg water<br />

per kg of dry air must be achieved by cooling incoming<br />

atmospheric air with a dry bulb temperature of 25.0°C and a<br />

wet bulb temperature of 20.0°C.<br />

a. To what temperature must the incoming air–water vapor<br />

mixture be cooled to achieve a humidity ratio of 5.00 ×<br />

10 −3 kg water per kg dry air?<br />

b. How much water must be removed per kg of dry air to<br />

achieve this state?<br />

42. Outside atmospheric air with a dry bulb temperature of 90.0°F<br />

and a wet bulb temperature of 85.0°F is to be passed through<br />

an air conditioning device so that it enters a house at 71.0°F<br />

and 40.0% relative humidity. The process consists of two steps.<br />

Table 12.6 Problem 33<br />

City T WB T DB ϕ ω T DP P w<br />

Berlin 21.0°C 32.0°C<br />

Chicago 75.0°F 97.0°F<br />

Hong Kong 28.0°C 33.0°C<br />

New York City 75.0°F 93.0°F<br />

Paris 20.0°C 31.0°C<br />

Rome 23.0°C 36.0°C<br />

Tokyo 79.0°F 92.0°F

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