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Modern Engineering Thermodynamics

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6.5 Nozzles and Diffusers 175<br />

m<br />

(a) Nozzle<br />

FIGURE 6.3<br />

Nozzles and diffusers.<br />

±Q<br />

m<br />

±Q<br />

W = 0 W = 0<br />

(b) Diffuser<br />

diffusers perform opposite functions. In their simplest<br />

form, a nozzle is merely a converging duct and a diffuser<br />

is merely a diverging duct, as shown schematically<br />

in Figure 6.3. 3<br />

Most commercial nozzles and diffusers are well insulated<br />

(adiabatic). However, they need not be, and therefore<br />

may have either a heat loss or a heat gain. On the<br />

other hand, the simple mechanical nature of nozzles<br />

and diffusers prevents them from either performing or<br />

absorbing work. Therefore, they can generally be taken<br />

to be aergonic devices.<br />

Since both nozzles and diffusers are clearly single inlet, single outlet devices, we can carry out an analysis of their<br />

steady state operation by using the modified energy rate balance of Eq. (6.12). Also, both nozzles and diffusers<br />

are either oriented horizontally, as shown in Figure 6.3, so that Z in = Z out or have such small changes in height<br />

between the inlet and outlet that the enthalpy change dominates the specific potential energy change, as discussed<br />

previously. This allows us to neglect the change in flow stream specific potential energy in nozzle and diffuser<br />

analysis.<br />

However, the flow stream specific kinetic energies are not necessarily negligible, because in both nozzles and<br />

diffusers, at least one of the flow streams normally has a high velocity. Consequently, we ignore the low-speed<br />

flow stream specific kinetic energy in each case and set V in ≈ 0 for the nozzle and V out ≈ 0 for the diffuser.<br />

At this point, we have developed the following set of assumptions for these devices:<br />

Nozzle<br />

Diffuser<br />

_W = 0 _W = 0<br />

Z in − Z out ≈ 0 Z in − Z out ≈ 0<br />

V in ≈ 0 V out ≈ 0<br />

Applying these assumptions for nozzles to the modified energy rate balance of Eq. (6.12) gives the following<br />

results:<br />

or<br />

_Q − 0 _mðh in − h out − V 2 out /2g c + 0Þ = 0<br />

V out<br />

= ½2g c ð _Q / _m + h in − h out ÞŠ 1/2 (6.15)<br />

nozzle<br />

Notice that adding heat to the nozzle increases the outlet velocity, whereas removing heat decreases it. If the<br />

nozzle is insulated (adiabatic), then _Q = 0 and<br />

p<br />

V out<br />

= ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi<br />

2g c ðh in − h out Þ<br />

(6.16)<br />

adiabatic<br />

nozzle<br />

Applying the previous assumptions for diffusers to the modified energy rate balance of Eq. (6.12) gives the<br />

following results:<br />

_Q + _m h in − h out + V 2 in /2g c<br />

= 0<br />

or<br />

h out<br />

= h in + Vin 2 /2g c + _Q / _m (6.17)<br />

diffuser<br />

Thus, heat added to a diffuser increases the outlet specific enthalpy, whereas heat removal reduces it. For an<br />

insulated (adiabatic) diffuser, we have<br />

h out<br />

= h in + V adiabatic<br />

in 2 /2g c (6.18)<br />

diffuser<br />

3 This figure is accurate only for subsonic flow. When the flow becomes supersonic, the relative shapes of nozzles and diffusers are not<br />

the same as those shown here.

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