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Modern Engineering Thermodynamics

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354 CHAPTER 10: Availability Analysis<br />

Problems (*indicates problems in SI units)<br />

1. Determine the potential for the following vector field:<br />

! ! ! !<br />

A = yi + xj + 0k :<br />

2. Compute the vector field for the following potential:<br />

P = ax + by + cz.<br />

3. Compute the vector field for the following potential:<br />

P = 3x 3 +2y 2 − z +7.<br />

4. Compute the vector field for the following potential:<br />

P = 5x 2 y/z + sin(x).<br />

5. Coulomb’s law of the electrostatic force of attraction between<br />

two isolated charges, Q 1 and Q 2 , separated by a distance r is<br />

!<br />

F = ðQ1 Q 2 /4πεr 2 ! !<br />

Þ ir, where ir is the unit vector pointing along<br />

the line of centers of the charges and ε is the dielectric constant<br />

of the medium containing the charges. Show that this force has a<br />

potential given by P = Q 1 Q 2 /4πεr:<br />

6. Newton’s law for the gravitational force between to bodies of<br />

mass m 1 and m 2 separated by a distance r is ! F =ðGm 1 m 2 /r 2 !<br />

Þ i r,<br />

!<br />

where G is the gravitational constant and i r is a unit vector<br />

pointing along the line of centers of the masses. Determine the<br />

gravitational potential for this force and show that it satisfies<br />

the Laplace equation in cylindrical coordinates,<br />

∇ 2! !<br />

F = ∂2 F<br />

∂r 2 + 1 ∂ ! F<br />

r ∂r + 1 ∂ 2!<br />

F !<br />

r 2 ∂θ 2 + ∂2 F<br />

∂z 2<br />

7.* The total energy contained in a closed rigid system is 550. kJ<br />

and its total entropy is 2.7521 kJ/K. The ground state total<br />

energy, total entropy, and absolute temperature of the system<br />

are 50.0 kJ, 1.0000 kJ/K, and 273 K, respectively. Determine<br />

the maximum reversible work this system can produce.<br />

8.* The total energy contained in a closed, sealed, rigid can of<br />

tuna is 3000. J with a total entropy of 2.8330 J/K. The ground<br />

state total energy, total entropy, and temperature of the system<br />

are 100.0 J, 0.0275 J/K, and 20.0°C, respectively. Determine<br />

the maximum reversible work available from the can of tuna.<br />

9. The total energy contained in a closed, sealed, rigid can of<br />

carbonated soda is 10.0 Btu with a total entropy of 0.0739<br />

Btu/R. The ground state total energy, total entropy, and<br />

temperature of the system are 1.00 Btu, 0.0619 Btu/K, and<br />

70.0°F, respectively. Determine the maximum reversible work<br />

available from the can of soda.<br />

10.* An inventor claims to have developed a new closed, sealed<br />

battery that can produce a maximum reversible work of 3.80<br />

kJ. The total energy contained in the battery is 2.00 kJ with a<br />

total entropy of 7.5150 J/K. If the ground state total energy<br />

and total entropy are 100. J and 0.5660 J/K, respectively, what<br />

ground state temperature is required to meet the inventor’s<br />

maximum reversible work claim?<br />

11. As a designer, you are required to develop a new closed, sealed<br />

thermal energy storage cell that has a maximum reversible work<br />

output of 500. Btu. The ground state total energy, total entropy,<br />

and temperature are 5.00 Btu, 0.11690 Btu/R, and 50.0°F,<br />

respectively. If the total entropy of the cell must be ten times its<br />

ground state value, what should the total energy of the cell be?<br />

12. An open bucket containing 30.0 lbm of liquid water at 70.0°F<br />

is sitting 6 ft above the floor on a ladder. Determine the total<br />

availability of the water in the bucket relative to the floor. The<br />

local environment is at 14.7 psia and 70.0°F.<br />

13.* An open bucket containing 14.0 kg of liquid water at 20.0°C is<br />

spun on a rope in a horizontal plane 2.00 m above the floor<br />

with a tangential velocity of 5.00 m/s. Determine the total<br />

availability of the water in the bucket relative to the floor. The<br />

local environment is at 0.101 MPa and 20.0°C.<br />

14.* Determine the total availability of a 7.00 × 10 −3 kg<br />

incompressible lead bullet traveling vertically at 1000. m/s at a<br />

height of 50 m above the ground. The temperature of the bullet<br />

is 150.°C and its specific heat is 0.167 kJ/kg·K. The local<br />

environment is at 0.101 MPa and 20.0°C.<br />

15.* A stationary tethered balloon contains helium gas (an ideal<br />

gas here) at 0.00°C and 0.0700 MPa at a height of 1000. m.<br />

Determine the specific availability of the helium in the<br />

balloon relative to the ground, where the local environment is<br />

at p 0 = 0.101 MPa and T 0 = 20.0°C.<br />

16.* The air (an ideal gas here) in the ballast tanks of a submarine is<br />

at 10.0°C and 1.50 MPa when the submarine is cruising at 3.00<br />

m/s, 100. m below sea level. Determine the specific availability<br />

of the air in the ballast tanks relative to sea level where the local<br />

environment is at 0.101 MPa and 20.0°C.<br />

17. Integrate Eq. (7.52) and use Eqs. (10.13a) and (10.14a) to<br />

determine the irreversibility and total availability change for<br />

an aergonic closed system in which the temperature increases<br />

from T 1 = 70.0°F toT 2 = 200.°F for the cases where the heat<br />

transfer varies with the system absolute temperature according<br />

to the relationships<br />

a. Q = K 1 T (convection).<br />

b. Q = K 2 T 4 (radiation)<br />

where K 1 = 3.70 Btu/R and K 2 = 5.40 × 10 −4 Btu/R 4 .The<br />

system boundary is maintained isothermal at 350.°F and the<br />

local environment is at 14.7 psia and 70.0°F.<br />

18. The temperature distribution due to conduction heat transfer<br />

inside a flat plate with an internal heat generation is given by<br />

T = T 0 +(T s − T 0 )(x/L) 2 , where T s is the surface temperature at<br />

x = L,andT 0 is the centerline temperature at x = 0 (Figure 10.23).<br />

Use Eqs. (7.66) and (10.13b) to determine a formula for the<br />

steady state irreversibility rate for this system.<br />

T s<br />

FIGURE 10.23<br />

Problem 18.<br />

19. A current of 100. A is passed through a 6.00 ft long stainless<br />

steel wire 0.100 inch in diameter. The electrical resistivity of<br />

the wire is 1.97 × 10 −5 Ω ·in, and its thermal conductivity is<br />

x<br />

L<br />

T s

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