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Modern Engineering Thermodynamics

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10.7 Closed System Availability Balance 329<br />

CRITICAL THINKING<br />

How do Eqs. (10.17) and (10.19) change for steady state processes? Does a system have to be steady state for dV/dt to be<br />

zero? If a system is steady state, does that necessarily mean that dV/dt and dA/dt are both zero?<br />

(a) T b > T 0 (b) T b < T 0<br />

System boundary<br />

at temperature T b<br />

System boundary<br />

at temperature T b<br />

Q<br />

A<br />

Q<br />

A<br />

Q<br />

A<br />

Local surroundings<br />

at temperature T 0<br />

Q<br />

A<br />

FIGURE 10.8<br />

(a) When T b > T 0 , the heat transfer and the associated availability transfer are both in the same direction (either both into or both out of<br />

the system). (b) When T b < T 0 , the heat transfer and the associated availability transfer are in opposite directions.<br />

If the system has a single heat transfer mode occurring at a constant system boundary temperature T b ,thenEqs.<br />

(10.16) and (10.17) reduce to<br />

<br />

1 − T <br />

0<br />

ð<br />

T 1 Q 2 Þ − 1 W 2 + p 0 ðV 2 − V 1Þ − 1 I 2 = ðA 2 − A 1 Þ system = ½mða 2 − a 1 ÞŠ system (10.18)<br />

bi<br />

and<br />

<br />

1 − T <br />

<br />

0 _Q − _W + p<br />

dV<br />

0<br />

T b<br />

dt − _I =<br />

dA <br />

dt<br />

system<br />

(10.19)<br />

Since availability represents the maximum useful reversible work that a system produces, each term in the availability<br />

balance must have this same meaning. Note that the heat transport of availability (Eqs. (10.9) and<br />

(10.10)) represents the maximum reversible work that a Carnot engine produces while operating between isothermal<br />

reservoirs at temperatures T and T 0 (see Eqs. (7.9) and (7.16)). The work transport of availability<br />

(Eq. (10.11)) corresponds to the difference between the actual work and the reversible work necessary to move<br />

the local environment if the system changes volume during a process. The irreversible loss of available energy<br />

associated with the actual heat and work transports of availability are contained in the irreversibility term I. This<br />

term accounts for the difference between an actual irreversible process and a hypothetical reversible process.<br />

Note that the availability gain can be either positive or negative (a system can gain or lose available energy during<br />

a process), and the heat and work availability transports can also be either positive or negative. However,<br />

Eq. (10.14) requires that the irreversibility must always be positive (I ≥ 0) because of its relation to the entropy<br />

production and the second law of thermodynamics (i.e., S P ≥ 0).<br />

When T b is greater than T 0 , the heat transfer and the associated availability transfer are in the same direction<br />

(either both into or both out of the system). However, when T b is less than T 0 , they are in opposite directions.<br />

Figure 10.8 illustrates this point and the following examples illustrate the use of this material.<br />

EXAMPLE 10.4<br />

A constant pressure piston-cylinder apparatus contains 1.00 kg of saturated liquid water at 120.°C. Heat is added to this system<br />

until the contents reach a quality of 50.0%. The surface temperature of the cylinder is constant at 130.°C. Determine<br />

the irreversibility of this process. The local environment (ground state) is at p 0 = 0.101 MPa and T 0 = 20.0°C = 293 K.<br />

(Continued )

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