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Modern Engineering Thermodynamics

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6.2 Mass Flow Energy Transport 169<br />

theslugmovesadistancej V ! jdt = Vdt and sweeps out an incremental volume dV = AV dt, which has an<br />

associated mass of dm = ρ dV = ρAV dt: Dividing by dt gives<br />

<br />

dm<br />

= ð _mÞ<br />

dt<br />

flow stream = ðρAVÞ flow stream (6.1)<br />

flow stream<br />

This equation is a very convenient way to calculate the flow stream mass flow rate from the easily measured<br />

variables of density (ρ), cross-sectional area (A), and average fluid velocity ðj V ! j = VÞ:<br />

The incremental energy required to push the mass slug across the system boundary and into the system is the<br />

product of the force acting on it, p × A, and the distance moved, dL. Consequently, the flow work energy increment<br />

is<br />

dW mass<br />

flow<br />

= − pA dL = − pdV = − p dm = − pv dm<br />

ρ<br />

where v =1/ρ is the specific volume of the slug. The flow work is negative here because adding dm to the system<br />

represents work done on the system.<br />

The total mass flow energy entering the system with this incremental mass is then<br />

dE mass<br />

= dE m − dW mass<br />

flow<br />

flow<br />

= ðu + ke + peÞ dm + ðpvÞ dm<br />

= ðu + pv + ke + peÞ dm<br />

Because the sum of the terms u and pv always appears in this equation, it is convenient to combine them into a<br />

single term (as explained in Chapter 3) called specific enthalpy, h = u + pv.<br />

In general, we have more than one mass flow stream in any given open system. To accurately account for all the<br />

mass flow energies, we sum them in two groups. One group accounts for all inlet flow streams and the other<br />

for all exiting flow streams. Therefore, we write<br />

dE mass<br />

flow<br />

= ∑<br />

inlet<br />

ðh + ke + peÞ dm − ∑ ðh + ke + peÞ dm<br />

outlet<br />

On dividing this equation through by dt, we obtain<br />

_E mass<br />

= ∑<br />

flow inlet<br />

_mðh + ke + peÞ − ∑<br />

outlet<br />

_mðh + ke + peÞ (6.2)<br />

and on integration of this equation, we obtain<br />

1<br />

E mass<br />

flow<br />

!<br />

2<br />

Z 2<br />

Z 2<br />

= ∑ _mðh + ke + peÞ dt − ∑ _mðh + ke + peÞ dt (6.3)<br />

inlet<br />

outlet<br />

1<br />

1<br />

where ke = V 2 /2g c and pe = gZ/g c are the specific kinetic and potential energies of the flow streams at the point<br />

where they cross the system boundary. Note that these equations already contain the proper thermodynamic<br />

signs for input (+) and output (−) mass flow energy transport.<br />

Each flow stream has its own average velocity V and height Z; in addition, the center of gravity of the entire<br />

system has unique and usually different V and Z values (see Figure 6.1). The student must be careful not to get<br />

these velocities and heights confused.

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