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Modern Engineering Thermodynamics

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15.3 Organic Fuels 597<br />

ANSWERS SOMETIMES COME IN DREAMS!<br />

In the early part of the 19th century, chemists were puzzled by the fact that it was possible to construct two seemingly<br />

different compounds that had dissimilar physical properties yet identical chemical formulae. For example, ethanol<br />

and dimethyl ether both have the same chemical formula, C 2 H 6 O, yet ethanol boils at 79°C while dimethyl ether boils at<br />

−24°C. Materials that have the same chemical formula but dissimilar physical properties are called isomers. The isomer<br />

puzzle was solved by the German chemist Friedrich August Kekulé (1829–1896) in a dream while dozing on the top deck<br />

of a horse-drawn bus in London. In his dream, he realized that the atoms of a molecule could be arranged in different geometric<br />

structures; and in 1858, he introduced the schematic notation, still used, in which bonds between atoms are represented<br />

by lines drawn between their corresponding chemical symbols (e.g., H 2 as H—H). He was then able to show that<br />

isomers were simply the result of different bonding patterns. For example, butane (C 4 H 10 ) has the isomers n-butane, which<br />

boils at −0.5°C, and isobutane, which boils at −12°C. (The n prefix is always used to denote the normal, or chainlike, structure,<br />

whereas the iso prefix is used to denote the branched structure.) These two isomer bonding patterns are shown in<br />

Figures 15.2 and 15.3.<br />

H H H H<br />

C C C C<br />

H H H<br />

H C C C<br />

H<br />

H<br />

H<br />

H H H H<br />

n-Butane<br />

(normal butane)<br />

(C 4 H 10 )<br />

FIGURE 15.2<br />

n-Butane and isobutane.<br />

H H<br />

H C H<br />

H<br />

Isobutane<br />

(C 4 H 10 )<br />

H<br />

H H<br />

C C<br />

H H<br />

H<br />

Ethane (C 2 H 6 )<br />

(alkane, saturated)<br />

H<br />

H<br />

H<br />

C C H C C H<br />

H<br />

Ethylene (C 2 H 4 )<br />

(alkene, unsaturated)<br />

Acetylene (C 2 H 2 )<br />

(alkyne, unsaturated)<br />

FIGURE 15.3<br />

Ethane (alkane, saturated), ethylene (alkene, unsaturated), and<br />

acetylene (alkyne, unsaturated).<br />

Another 19th century hydrocarbon curiosity was the existence of the two classes, aliphatic (fatty) and aromatic (fragrant)<br />

compounds. Aromatic hydrocarbons always had at least six carbon atoms and a smaller proportion of hydrogen atoms<br />

than the aliphatic hydrocarbons. In 1865, Kekulé again found the solution in a dream. He envisioned a six-carbon chain<br />

closing on itself to form a ring, like a snake biting its own tail, and he concluded that the aromatic compounds contain<br />

such rings whereas the aliphatic compounds contain only straight chains.<br />

Within the aliphatic group, the alkanes are characterized by having carbon atoms with single bonds between them, while<br />

the alkenes have carbon atoms with double bonds between them, and alkynes have carbon atoms with triple bonds between<br />

them. If all the bonds within an organic compound are single, then the compound is said to be saturated; but if multiple<br />

bonds exist between any two carbon atoms in the compound, it is said to be unsaturated. Thus, the alkanes are all saturated<br />

hydrocarbons, while all the remaining hydrocarbons are unsaturated.<br />

Also, its combustion with excess air using 100.(x) percent theoretical air (i.e., 100.(x − 1) percent excess air),<br />

where x ≥ 1.0, is<br />

C n H m + xn+ ð m/4Þ½O 2 + 3:76ðN 2 ÞŠ ! nðCO 2 Þ + ðm/2ÞðH 2 OÞ<br />

+ ðx − 1Þðn + m/4ÞðO 2 Þ<br />

+ xð3:76Þðn + m/4ÞðN 2 Þ<br />

(15.3b)<br />

And its combustion in deficit air using 100.(y) percent theoretical air (i.e., 100.(1 − y) percent deficit air), where<br />

ð2n + mÞ ÷ ð4n + mÞ ≤ y ≤ 1:0, is<br />

C n H m + yn+ ð m/4Þ½O 2 + 3:76ðN 2 ÞŠ ! nð2y − 1Þ − mð1 − yÞ/2 ðCO 2 Þ<br />

+ ð2n + m/2Þð1 − yÞðCOÞ + ðm/2ÞðH 2 OÞ<br />

+ yð3:76Þðn + m/4ÞðN 2 Þ<br />

(15.3c)<br />

In Eq. (15.3c), it has been assumed that the hydrogen is much more reactive than the carbon, so it will take up all<br />

the oxygen it needs to be converted into water. This leaves only the carbon subject to incomplete combustion.

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