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Modern Engineering Thermodynamics

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13.2 Part I. Engines and Vapor Power Cycles 455<br />

EXAMPLE 13.2<br />

In 1807, Robert Fulton (1765-1815) successfully piloted his walking beam paddlewheel steamboat Clermont from New York<br />

City to Albany, New York (see Figure 13.5). His single-cylinder engine was made by the Boulton and Watt steam engine<br />

manufacturing company in England and produced 20.0 hp with a piston diameter of 2.00 ft and a piston stroke of 4.00 ft.<br />

The two side paddlewheels were 15.0 ft in diameter. The boiler was made of copper and it weighed 4,000 lbf dry. If the<br />

engine had a duty of 35.0 million and ran at 18.0 strokes per minute, then determine:<br />

a. The average pressure of the cycle.<br />

b. The actual thermal efficiency of the engine.<br />

c. The heat rate produced by the boiler.<br />

Solution<br />

a. The average cylinder pressure of the engine can be determined by setting the calculated power produced by the piston<br />

equal to the actual power produced by the engine, or<br />

_W out = ðp avg Þ × ðPiston displacementÞ × ðPiston strokes/minÞ<br />

" !<br />

#<br />

πðD piston Þ 2<br />

= ðp avg Þ ×<br />

ðPiston strokeÞ × ðStrokes/minÞ<br />

4<br />

<br />

πð2:00Þ 2 <br />

<br />

= ðp avg Þ ×<br />

ft 2 ð4:00 ft/StrokeÞ × ð18:0 Strokes/minÞ<br />

4<br />

= ðp avg Þ × ð226 ft 3 /minÞ<br />

Now,<br />

_W out = 20 hp = (20 hp)(33,000 ft ·lbf/hp·min) = 660,000 ft·lbf/min, so<br />

b. From Eq. (13.1), we have<br />

p avg = 660,000 ft . lbf/min<br />

226 ft 3 /min<br />

η T ð%Þ =<br />

= 2918 lbf/ft 2 2918 lbf/ft2<br />

= = 20:3<br />

144 in 2 lbf/in2<br />

2<br />

/ft<br />

Duty<br />

35:0 × 106<br />

× 100 =<br />

8<br />

8:5 × 10 8:50 × 10 6 = 4:12%<br />

c. The heat rate produced by the boiler can be found from the thermodynamic definition of the thermal efficiency as<br />

η T = _W out = _Q boiler . Then,<br />

_Q boiler =<br />

_ W out<br />

η T<br />

= ð20:0hpÞð2545 Btu/hp . hÞ<br />

0:0412<br />

= 1:24 × 10 6 Btu/h<br />

Exercises<br />

4. Determine the average cycle pressure in Example 13.2 if the engine produces 30.0 instead of 20.0 hp and all the other<br />

variables remain unchanged. Answer: p avg = 27.3 psi.<br />

5. Determine the actual thermal efficiency of the engine in Example 13.2 if it has a duty of 26.0 × 10 6 instead of<br />

35.0 × 10 6 and all the other variables remain unchanged. Answer: η T = 3.06%.<br />

6. Determine the heat rate produced by the boiler in Example 13.2 if the engine produces 25.0 instead of 20.0 hp, and all<br />

the other variables remain unchanged. Answer: _Q boiler = 1.55 × 10 6 Btu/h.<br />

WHAT IS A STEAM ENGINE INDICATOR?<br />

In an effort to continue to improve the performance of his steam engines, Watt wanted to know how the pressure varied<br />

with piston position inside the cylinder as the engine was running. About 1790, he developed an ingenious device for this<br />

purpose (Figure 13.6), which he called a steam engine indicator. This device drew the actual pressure–volume diagram of the<br />

steam inside the cylinder as the engine was running. Such p V diagrams soon became known as indicator diagrams, and the<br />

area enclosed by these diagrams represented the reversible work produced inside the engine.<br />

(Continued)

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