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Modern Engineering Thermodynamics

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712 CHAPTER 17: <strong>Thermodynamics</strong> of Biological Systems<br />

WHAT ABOUT BIRDS?<br />

The pulse to breathing rate ratio is about 9.0 for all birds (regardless of their size) because birds have a continuous flow of<br />

air in only one direction through their lungs, in contrast to the two-way in-out breathing of mammals. The unidirectional<br />

air flow in birds is also countercurrent (in the opposite direction to) the blood flow in the lungs, thus improving the efficiency<br />

of gas exchange.<br />

itself is proportional to L 3 . Therefore, the ratio of blood flow rate to heart volume varies with L 2 /L 3 = L −1 ,and<br />

consequently, the heart pulse rate also varies with L –1 . For mammals, the heart pulse rate has been correlated<br />

with body mass according to<br />

where the body mass m is in kilograms.<br />

Heart pulse rate ðin beats per minuteÞ = 241ðm −0:25 Þ = 241<br />

m 1/4 (17.18)<br />

The same argument can be made for the respiratory system. The ratio of the gas transport rate through the lung<br />

wall to the lung volume also varies with L –1 , and the breathing rate is also proportional to L –1 . Experimentally,<br />

we find that the ratio of pulse rate to breathing rate is constant at about 4.5 in all mammals regardless of their<br />

size. The breathing rate for mammals has been correlated with body mass as<br />

Breathing rate ðin breaths per minuteÞ = 54:0ðm −0:25 Þ = 54:0<br />

(17.19)<br />

m 1/4<br />

where the body mass m is in kilograms.<br />

EXAMPLE 17.7<br />

As a famous biomedical engineer, you are challenged on your medical exam to determine the heart rate and respiratory rate<br />

of a 0.0300 kg mouse, a 70.0 kg human, and a 4000. kg elephant.<br />

Solution<br />

The heartbeat rate for mammals in beats per minute is given by Eq. (17.18) as<br />

so the heartbeat rates of the mouse, human, and elephant are<br />

Heartbeat rate = 241ðm −0:25 Þ Beats/min<br />

ðHeartbeat rateÞ mouse = 241ð0:0300 −0:25 Þ = 579: Beats/min<br />

ðHeartbeat rateÞ human = 241ð70:0 −0:25 Þ = 83:3 Beats/min<br />

ðHeartbeat rateÞ elephant = 241ð4000: −0:25 Þ = 30:3 Beats/min<br />

The respiratory rate of mammals in breaths per minute is given by Eq. (17.19) as<br />

So the breathing rates of the mouse, human, and elephant are<br />

Respiratory ðbreathingÞ rate = 54:0ðm −0:25 Þ Breaths/min<br />

ðBreathing rateÞ mouse = 54:0ð0:0300 −0:25 Þ = 130: Breaths/min<br />

ðBreathing rateÞ human = 54:0ð70:0 −0:25 Þ = 18:7 Breaths/min<br />

ðBreathing rateÞ elephant<br />

= 54:0ð4000: −0:25 Þ = 6:79 Breaths/min<br />

Exercises<br />

19. Determine the heatbeat rate of a 2.80 kg house cat. Answer: 186 beats/min.<br />

20. Determine the breathing rate of a 700. kg racehorse. Answer: 10.5 breaths/min.<br />

21. Since whales are mammals, determine the heart rate of a 136,000 kg (150. ton) blue whale. Answer: 12.6 beats/min.<br />

Because plants lack mobility, their size criteria are generally simpler than those for animals. The main strength<br />

concerns in plants center on the buckling of their central trunk and excessive deflections of their cantilevered<br />

limbs. Consider a circular cylinder of height h and diameter d. Then, for slender cylinders ðh/d > 25Þ the critical<br />

height for a cylinder buckling under its own weight can be shown to be<br />

<br />

h critical = 0:85 E 1/3d<br />

2/3<br />

γ<br />

(17.20)

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