05.04.2016 Views

Modern Engineering Thermodynamics

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

238 CHAPTER 7: Second Law of <strong>Thermodynamics</strong> and Entropy Transport and Production Mechanisms<br />

10 3<br />

10 2<br />

10 1<br />

Silicon<br />

10 0 0 100 200 300 400 500 600 700 800 900 1000<br />

Resistivity (Ω.m)<br />

10 −1<br />

10 −2<br />

10 −3<br />

10 −4<br />

10 −5<br />

10 −6<br />

10 −7<br />

10 −8<br />

10 −9<br />

10 −10<br />

Germanium<br />

Tungsten<br />

Temperature (K )<br />

Copper<br />

FIGURE 7.22<br />

The variation of electrical resistivity with temperature. (Source: Reprinted by permission of the author from Lenert, L. H., 1968.<br />

Semiconductor Physics, Devices, and Circuits. Charles E. Merrill Publishing, Columbus, OH.)<br />

Ohm’s law is a simple mathematical model used for the resistive dissipation of electrical work mode energy. In<br />

this model, the entropy production rate per unit volume due to electrical resistance is<br />

ðσ W Þ elect = Je 2 ρ e/T<br />

where J e = I/A is the electrical current per unit area (i.e., the electrical current flux), ρ e = R e A/L is the electrical<br />

resistivity, R e is the total electrical resistance of the conductor, L and A are the length and cross-sectional area of<br />

the conductor, and T is the local internal absolute temperature of the conductor. Then, Eq. (7.70) gives<br />

Z<br />

<br />

_S p W =<br />

elect V<br />

The electrical current flux J e is often expressed by the one-dimensional Ohm’s law as<br />

<br />

dϕ<br />

J e = −k e<br />

dx<br />

Je 2ρ e<br />

dV (7.73)<br />

T<br />

where k e = 1/ρ e is the electrical conductivity and ϕ is the electrical potential (i.e., voltage). The relation between<br />

ρ e and T is shown in Figure 7.22 for various materials.<br />

For the special case of an isothermal system with uniform properties and a constant current density, Eq. (7.73) reduces<br />

to this special case:<br />

Entropy production rate due to electrical resistance:<br />

_S P<br />

<br />

W<br />

elect<br />

ðspecialÞ<br />

= J2 e ρ eV<br />

T<br />

<br />

<br />

= ðI/AÞ2 × ðR e A/LÞ × LA<br />

= I2 R e<br />

T<br />

T<br />

(7.74)<br />

EXAMPLE 7.12<br />

A new high-temperature silicon computer chip 1.00 × 10 −3 m by 5.00 × 10 −3 m by 10.0 × 10 −3 m long with uniform properties<br />

operates isothermally at 600. K and draws a constant electrical current of 0.10 A. Determine the entropy production<br />

rate of the chip.<br />

Solution<br />

First, draw a sketch of the system (Figure 7.23).

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!