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Modern Engineering Thermodynamics

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6.9 Shaft Work Machines 189<br />

1<br />

Basement wall<br />

p 1 = 85.0 psig<br />

City<br />

water<br />

main<br />

2<br />

p 2 = 10.0 psig<br />

W shaft<br />

To water<br />

meter<br />

FIGURE 6.12<br />

Example 6.5.<br />

Now, (2.50 gal/h)(0.13368 ft 3 /gal)(1 h/3600 s) = 9.283 × 10 −5 ft 3 /s. So,<br />

_W shaft = ð9:283 × 10 −5 ft 3 /sÞ½ð85:0 − 10:0Þ lbf/in 2 Šð144 in 2 /ft 2 Þ<br />

= 1:00 ft.lbf/s:<br />

= ð1:00 ft.lbf/sÞ½1 hp/ð550 ft.lbf/sÞŠ = 1:82 × 10 −3 hp<br />

= ð1:82 × 10 −3 hpÞð746 W/hpÞ = 1:36 W<br />

Therefore, the amount of power we get out of such a device would be extremely low and probably would not justify its<br />

initial expense. 7<br />

Suppose, now, we calculate an instantaneous power instead of the average power. For this calculation, we assume an instantaneous<br />

water flow of 5 gal/min. Then, the hydraulic power produced is<br />

= ð1:36 WÞð5 gal/minÞð60 min/hÞ½1/ð2:50 gal/hÞŠ<br />

_W Shaft instantaneous<br />

=163 W<br />

Which is more reasonable. This is enough power to light two 75 W lightbulbs, but since this water flow rate does not occur<br />

continuously the bulbs would not be lit very often.<br />

Exercises<br />

12. What flow rate of water would be required in Example 6.5 to produce 1.00 hp of shaft output power?<br />

Answer: _m w = 22.9 gal/min.<br />

13. Determine the inlet water pressure required in Example 6.5 to produce a continuous shaft output power of 163 W with<br />

a water flow rate of 2.50 gal/h. Answer: (p inlet ) w = 9.00 × 10 3 psig.<br />

14. It has been suggested that, by installing a hydraulic turbine powered electric generator on the main water pipe supplying<br />

all the open flow devices in a house (sinks, toilets, washing machines, etc.), some of the water flow energy that is<br />

ordinarily wasted could be converted into useful electrical energy. Discuss the feasibility of this proposal in a short<br />

paragraph. Hint: Consider the economic costs of such a system and the required payback time. Estimate how much<br />

electrical power could be generated by analyzing the water flow in your home.<br />

7 This conclusion might change if we were dealing with the domestic water flow into a large factory or multistory office or apartment building.<br />

EXAMPLE 6.6<br />

Determine the quality of the steam at the outlet of an insulated steam turbine producing 2000. kJ of energy per kilogram of<br />

steam flowing through the turbine. The steam at the inlet of the turbine is at 2.00 MPa, 800.°C and the outlet pressure is<br />

1.00 kPa. Neglect any changes in specific kinetic or potential energy of the flow stream, and assume a steady state operation.<br />

Solution<br />

First, draw a sketch of the system (Figure 6.13).<br />

The system is open, and the unknown is the turbine’s outlet steam quality x 2 , as shown in Figure 6.13. The material is<br />

steam.<br />

(Continued )

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