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Modern Engineering Thermodynamics

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14.5 Vapor-Compression Refrigeration Cycle 543<br />

WHERE DID “MECHANICAL REFRIGERATION” COME FROM?<br />

The first vapor-compression refrigeration system was patented by Jacob Perkins (1766–1849) in 1834 (Figure 14.9). Though<br />

Perkins was an American, his refrigerator was made in England and was not an economic success. A similar machine was made<br />

in the United States in 1856 by Alexander Catlin Twinning (1801–1884), again with little financial success. In each case, the evaporator<br />

was immersed in a salt brine solution and the cold brine was used to make ice, but it attracted little attention for more<br />

than 20 years, after which natural refrigeration had begun to cause changes in people’s dietary habits. In 1855, James Harrison<br />

(1816–1893), a Scotsman who emigrated to Australia, produced a commercially successful refrigerator similar to Perkins’s for<br />

the manufacture of ice. Since natural ice is difficult to find in Australia, Harrison’s artificial ice machine was an instant success.<br />

Outdoor<br />

heat exchanger<br />

Supply duct<br />

Heated air<br />

Heat<br />

Indoor<br />

heat exchanger<br />

Return duct<br />

FIGURE 14.9<br />

Jacob Perkins’s 1834 refrigeration apparatus.<br />

Compressor<br />

EXAMPLE 14.3<br />

A refrigeration system for a supermarket is to be designed using R-22 to maintain frozen food at −15.0°C while operating in<br />

an environment at 20.0°C. The refrigerant enters the condenser as a saturated vapor and exits as a saturated liquid. Determine<br />

the COP for this refrigerator, using<br />

a. A reversed Carnot cycle operating between these temperature limits.<br />

b. An isentropic vapor-compression cycle with an isentropic expansion turbine installed between the high-pressure<br />

condenser and the low-pressure evaporator.<br />

c. An isentropic vapor-compression cycle with an aergonic, adiabatic, throttling expansion valve installed between the highpressure<br />

condenser and the low-pressure evaporator.<br />

Solution<br />

First, draw a sketch of the system (Figure 14.10).<br />

Q H<br />

Condenser<br />

3 2<br />

4<br />

W T<br />

Evaporator<br />

Q L<br />

1<br />

W C<br />

T<br />

3 2s<br />

4s 1<br />

s<br />

FIGURE 14.10<br />

Example 14.3, system sketch.<br />

a. Here, T H = 20.0 + 273.15 = 293.15 K, and T L = −15.0 + 273.15 = 258.15 K. Then, Eq. (14.5) gives<br />

T<br />

COP Carnot<br />

= L<br />

=<br />

T H − T L<br />

refrigerator<br />

258:15<br />

293:15 − 258:15 = 7:38 (Continued )

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