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Modern Engineering Thermodynamics

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11.4 Maxwell Equations 369<br />

then,<br />

<br />

∂s<br />

= −R/p<br />

∂p<br />

T<br />

so that ds T = –R(dp/p) T , where the subscript T is used to indicate that the temperature is to be held constant. This can be<br />

integrated for the constant temperature condition to give<br />

ðs 2 − s 1 Þ T = −R<br />

Z 2<br />

1<br />

ðdp/pÞ T + funcðTÞ = −R ln ðp 2 /p 1 Þ + funcðTÞ<br />

where func(T ) is an arbitrary function of integration. The function of integration here depends on the temperature T, and for<br />

an isothermal process, it is treated as a constant. Since we happen to know that the entropy relation for an ideal gas is in<br />

fact s 2 – s 1 = c p ln(T 2 /T 1 ) – R ln(p 2 /p 1 ), it is easy to see that the function of integration here is simply c p ln(T 2 /T 1 ).<br />

The following exercises reinforce the concepts presented in Example 11.5.<br />

Exercises<br />

13. Use the other Maxwell equation (Eq. 11.15) available for the solution of Example 11.5 to find a different ideal gas<br />

entropy relation. Answer: (s 2 – s 1 ) T = R ln(v 2 /v 1 ) + func(T ).<br />

14. Show that (∂s/∂) p = (∂p/∂T ) s . Answer: Invert Eq. (11.14).<br />

15. Show that ðs 2 − s 1 Þ y<br />

= −<br />

Z 2<br />

1<br />

ð∂T/∂vÞ s<br />

dp + funcðvÞ. Answer: Use Eq. (11.13).<br />

Before we continue with our search for the illusive u, h, s equations in terms of p, v, T variables, the following<br />

example shows that the form taken by the Maxwell equations depends on the type of reversible work mode present<br />

in the system.<br />

EXAMPLE 11.6<br />

The equation of state for a nonlinear rubber band is given by<br />

F = KTðL/L o − 1Þ 2<br />

where F is the stretching force, L is the stretched length, L o is the initial length, K is the elastic constant, and T is the absolute<br />

temperature of the material. Then,<br />

a. Determine the Maxwell equations for this material.<br />

b. Show that the internal energy of this material is a function of temperature only.<br />

c. Determine the heat transfer required when the rubber band is stretched isothermally and reversibly from L o = 0.0700 m<br />

to L = 0.200 m at T = 20.0°C when K = 0.150 N/K.<br />

Solution<br />

The unknowns here are the Maxwell equations for this material, showing that the internal energy of this material is a function<br />

of temperature only and the heat transfer required when the rubber band is stretched isothermally and reversibly<br />

between two states.<br />

a. Since the reversible work mode involved in the stretching process is<br />

ðdWÞ rev<br />

= −FdL<br />

the Maxwell equations for this material can be easily obtained from those derived in the text by replacing p with –F and<br />

v with L/m = l, the specific length of the material. Then Eqs. (11.13) to (11.16) become<br />

<br />

∂T<br />

= ∂F <br />

∂l s ∂s l<br />

<br />

∂T<br />

= − ∂l <br />

∂F s ∂s F<br />

and<br />

<br />

∂F<br />

∂T l<br />

<br />

∂l<br />

∂T F<br />

<br />

= − ∂s <br />

∂l T<br />

<br />

= ∂s <br />

∂F T<br />

(Continued )

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