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Modern Engineering Thermodynamics

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510 CHAPTER 13: Vapor and Gas Power Cycles<br />

Intake valve<br />

remains open<br />

as piston begins<br />

moving up<br />

Intake valve<br />

is still open<br />

Intake valve<br />

finally closes<br />

and compression<br />

starts<br />

Compression<br />

completed followed<br />

by ignition and<br />

power stroke<br />

Clearance volume, V c<br />

Clearance volume, V c<br />

1<br />

1<br />

Pressure, p<br />

7s<br />

Intake valve closes<br />

at point 5<br />

Pressure, p<br />

7s<br />

Intake valve closes<br />

at point 5<br />

2s<br />

2s<br />

p atm<br />

4<br />

5<br />

Displacement, V d<br />

6<br />

3<br />

p atm<br />

4<br />

5<br />

Displacement, V d<br />

6<br />

3<br />

TDC<br />

BDC<br />

Volume, V d<br />

(a) Supercharged Miller cycle with late<br />

intake valve closing.<br />

TDC<br />

BDC<br />

Volume, V d<br />

(b) Supercharged Miller cycle with early<br />

intake valve closing.<br />

FIGURE 13.52<br />

The ideal supercharged Miller cycle with early and late intake valve closing.<br />

The Miller cycle has one additional benefit: When the intake air is compressed by a supercharger then cooled by<br />

an intercooler, it has a higher density and a lower temperature than that obtained by a piston compression<br />

alone, further increasing the engine’s efficiency.<br />

EXAMPLE 13.16<br />

A four-cylinder, 3.50 liter automobile engine operates on an ideal Miller cycle with early closing intake valves<br />

shown in Figure 13.52b. It has a compression ratio of 8.00 to 1 and an expansion ratio of 10.0 to 1. The turbocharger<br />

provides air at 200. kPa and 40.0ºC when the intake valve closes. The air–fuel ratio is 15.0 to 1 and the fuel has a<br />

heating value of 43,300 kJ/kg.UsingacoldASCwithk = 1.35, determine the temperature and pressure at all points of<br />

the cycle.<br />

Solution<br />

For each cylinder, the displacement volume is V d = 3.50/4 = 0.875 L = 8.75 × 10 –4 m 3 . The clearance volume, V c ,is<br />

calculated from the expansion ratio as ER = (V c + V d )/V c ,or<br />

V c = V d /ðER − 1Þ = ð8:75 × 10 −4 Þ/ð10:0 − 1Þ = 9:72 × 10 −5 m 3

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