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Modern Engineering Thermodynamics

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13.5 Operating Efficiencies 461<br />

13.5.4 Thermal Efficiency<br />

We also have to deal with three types of thermal efficiencies for work-producing or work-absorbing systems:<br />

isentropic, reversible (or indicated), and actual (or brake). These thermal efficiencies are defined mathematically in<br />

Table 13.2.<br />

Using these definitions, the isentropic efficiency of the adiabatic piston-cylinder work-producing prime mover of<br />

the Rankine cycle heat engine shown in Figure 13.9 is<br />

ðη s Þ prime<br />

mover<br />

ðh 1 − h 2 Þ<br />

= ðη s Þ pm =<br />

actual<br />

= h 1 − h 2<br />

ðh 1 − h 2 Þ isentropic h 1 − h 2s<br />

(13.4a)<br />

or<br />

h 1 − h 2 = ðh 1 − h 2<br />

Þ actual = ðh 1 − h 2s Þðη s Þ pm (13.4b)<br />

where h 2s is determined from p 2 (but not T 2 ) and the condition s 2s = s 1 , as shown in Figure 13.9. Similarly,<br />

the isentropic efficiency of the adiabatic work-absorbing condensate pump in the heat engine shown in<br />

Figure 13.9 is<br />

ð<br />

ðη s Þ pump<br />

= ðη s Þ p<br />

= h 4 − h 3 Þ isentropic<br />

= h 4s − h 3<br />

(13.5)<br />

ðh 4 − h 3 Þ actual<br />

h 4 − h 3<br />

where h 4s is determined from p 4 (but not T 4 ) and the condition s 4s = s 3 , as shown in Figure 13.9. If the fluid<br />

being pumped is an incompressible liquid (v = constant) with a constant specific heat c, then Eq. (7.33) of<br />

Chapter 7 clearly shows that any isentropic process that it undergoes must also be isothermal. That is, T 4s = T 3<br />

and consequently u 4s = u 3 . Then, for v 4s = v 4 = v 3 and (note that, for an isentropic pump, points 3 and 4s coincide<br />

on a T–s diagram but not on a p–v diagram, see Figure 13.9) p 4s = p 4 and<br />

h 4s − h 3 = u 4s − u 3 + p 4s v 4s − p 3 v 3<br />

= cT ð 4s − T 3 Þ+ v 3 ðp 4s − p 3 Þ<br />

= v 3 ðp 4 − p 3 Þ<br />

(13.6)<br />

Equation (13.5) can now be written as<br />

ðη s Þ incompressible<br />

liquid<br />

pump<br />

= v 3ðp 4 − p 3 Þ v 3 ðp 4 − p 3 Þ<br />

=<br />

h 4 − h 3 cT ð 4 − T 3 Þ+ v 3 ðp 4 − p 3 Þ<br />

(13.7)<br />

or<br />

h 4 − h 3 = ðh 4 − h 3 Þ actual = v 3 ðp 4 − p 3 Þ/ ðη s Þ p (13.8)<br />

Substituting Eqs. (13.4b) and (13.8) into the Rankine cycle thermal efficiency, Eq. (13.3) gives<br />

ð<br />

ðη T Þ Rankine = h 1 − h 2s Þðη s Þ pm − v 3 ðp 4 − p 3 Þ/ ðη s Þ p<br />

(13.9a)<br />

h 1 − h 3 − v 3 ðp 4 − p 3 Þ/ ðη s Þ p<br />

where (η s ) pm is the isentropic efficiency of the prime mover. The maximum possible Rankine cycle thermal<br />

efficiency occurs when both the prime mover and the condensate pump are isentropic: (η s ) pm = (η s ) p = 1.0, or<br />

ðη T Þ maximum<br />

Rankine<br />

= ðη T Þ isentropic<br />

Rankine<br />

= h 1 − h 2s − v 3 ðp 4 − p 3 Þ<br />

h 1 − h 3 − v 3 ðp 4 − p 3 Þ<br />

(13.9b)<br />

The phrase isentropic Rankine cycle thermal efficiency is used here to denote that the prime mover and the condensate<br />

pump are both isentropic (i.e., reversible and adiabatic). Clearly, the entire cycle is not isentropic, since<br />

thermal irreversibilities are associated with reheating the cold condensate returned to the hot boiler. This<br />

notation is necessary to distinguish between reversible Rankine cycles, in which the prime movers and pumps are<br />

modeled as reversible but are not adiabatic, and those Rankine cycles in which these items are modeled as both<br />

reversible and adiabatic (i.e., isentropic). This same notation is used in referring to other power and refrigeration<br />

cycles that contain isentropic components.

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