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Modern Engineering Thermodynamics

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316 CHAPTER 9: Second Law Open System Applications<br />

+Z<br />

Air<br />

(101.3 kPa)<br />

1<br />

Dam<br />

3<br />

H = 21.49 m<br />

Air<br />

turbine<br />

W T<br />

Exhaust<br />

water<br />

pipe<br />

4<br />

80.77 m<br />

Air entrained<br />

in downflow<br />

of water<br />

2<br />

Compressed air<br />

Seperation<br />

tank<br />

Air bubbles rise to surface<br />

FIGURE 9.34<br />

Problem 66.<br />

66.* Figure 9.34 is a schematic of a novel hydraulic air compressor<br />

built in Michigan in 1906 at the Victoria Copper Mining<br />

Company and operated until 1921. This plant used the power<br />

of falling water from the Ontonagon River to produce highpressure<br />

air with no moving mechanical parts. The falling<br />

water compressed entrained air bubbles, which were then<br />

separated from the water in a large underground separation<br />

tank. The efficiency of this system is defined to be rate of<br />

energy removed<br />

η =<br />

Rate of energy removed from the compressed air<br />

Net hydraulic power of the water<br />

= _m aðh 2 − h 3 Þ a<br />

_m w ðgH/g c Þ<br />

where the a subscript refers to the air and the w subscript<br />

refers to the water. Using the data given in Table 9.5,<br />

determine<br />

a. The separation tank temperature, assuming the air and water<br />

are in constant thermal equilibrium in an adiabatic<br />

downflow.<br />

b. The air turbine output power.<br />

c. The entropy production rate for the compressor, assuming it is<br />

completely adiabatic.<br />

In your analysis, assume air to be a constant specific heat ideal gas<br />

and water to be an incompressible liquid. Neglect any changes in<br />

kinetic energy of the air and the water. Note that the air turbine<br />

discharges to the atmosphere, so p 3 = p atm =101.3kPa.<br />

67.* A bottle of beer is emptied adiabatically at a rate of 0.100 kg/s.<br />

What is the rate of change of entropy of the contents of the beer<br />

bottle if the properties of the beer are<br />

h = 53:0 kJ/kg T = 10:0°C<br />

p = 0:1013 MPa s = 1:000 kJ/ðkg ⋅ KÞ<br />

and the entropy production rate is 0.0100 kJ/(s · K).<br />

Table 9.5 Data for the Victoria Hydraulic Air<br />

Compressor<br />

η = 57:4%<br />

p 2a = 882:6 kPa<br />

_m a = 5:430 kg/s<br />

_m w = 6119:1 kg/s<br />

T 1a = T 1w = 20:0°C<br />

H = 21:49 m<br />

Source: Data from W. Rice, “Performance of Hydraulic Gas Compressors.”<br />

ASME Journal of Fluids <strong>Engineering</strong> (December 1976), pp. 645–653.<br />

68. Helium at 70.0°F enters a 3.00 ft 3 rigid tank that is filled to a<br />

final pressure of 2200. psia. Assuming the tank is initially<br />

evacuated and that the helium behaves as an ideal gas with<br />

constant specific heats, determine the amount of entropy<br />

produced when the tank is filled (a) adiabatically and<br />

(b) isothermally at 70.0°F.<br />

69. Plot the isothermal to adiabatic entropy production ratio for<br />

filling an initially evacuated container with equal amounts of an<br />

incompressible liquid vs. the dimensionless ratio pv/(cT) asthis<br />

ratio ranges from 0.00 to 10.0.<br />

70.* A0.0370m 3 hydraulic cylinder is filled with 30.0 kg of oil (an<br />

incompressible liquid) from a supply at 20.0°C and 50.0 MPa.<br />

The specific heat of the oil is 1.83 kJ/(kg · K). Determine<br />

a. The entropy produced if the cylinder is filled isothermally at<br />

20.0°C.<br />

b. The final temperature and the entropy produced if the<br />

cylinder is filled adiabatically.<br />

71. Equation (9.47) shows that filling a rigid container adiabatically<br />

with an incompressible liquid produces less entropy than filling<br />

it isothermally. However, an adiabatic filling process produces a<br />

temperature rise in the vessel (see Eq. (6.35)) such that T final =<br />

T 2 > T 1 .<br />

a. Develop a formula for the additional entropy produced<br />

when the rigid container adiabatically filled with an<br />

incompressible liquid is cooled back to the initial<br />

temperature by submerging it into a large isothermal bath at<br />

temperature T1.<br />

b. Compare the total entropy produced by the adiabatic filling<br />

plus the cooling process described in part a with that produced<br />

during an isothermal filling process at temperature T 1 .<br />

Design problems<br />

The following are elementary open-ended design problems. The<br />

objective is to carry out a preliminary thermal design as indicated.<br />

A detailed design with working drawings is not expected unless<br />

otherwise specified. These problems do not have specific answers, so<br />

each student’s design is unique.<br />

72. A liquid cavitates when the local pressure drops below the<br />

saturation pressure and the liquid begins to vaporize, or boil.

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