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characterization, modeling, and design of esd protection circuits

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144 Chapter 5. Design <strong>and</strong> Optimization <strong>of</strong> ESD Protection Transistor Layout<br />

certain charging voltage, VHBM , the 1500Ω series resistor <strong>of</strong> the circuit is usually much<br />

larger than the impedance <strong>of</strong> the device under test, so we can think <strong>of</strong> both TLP <strong>and</strong> HBM<br />

testers as current sources, with the peak HBM current equal to VHBM /1500Ω. For the<br />

Advanced Micro Devices (AMD) 0.35µm technology studied in this chapter, we know<br />

from failure analysis that HBM <strong>and</strong> TLP failures are thermal rather than dielectric in<br />

nature. An identical failure mechanism leads us to believe that there may be some TLP<br />

pulse width for which the withst<strong>and</strong> current, ITLP,ws , <strong>of</strong> any structure is equal to the peak<br />

current <strong>of</strong> an HBM pulse at the withst<strong>and</strong> level <strong>of</strong> that structure. Note that from this point<br />

on the TLP failure current, It2 or Ifail , is assumed to be only infinitesimally larger than the<br />

withst<strong>and</strong> current (the maximum TLP current a structure can withst<strong>and</strong> without incurring<br />

damage), so all terms are used interchangeably.<br />

HBM <strong>and</strong> TLP current waveforms <strong>and</strong> the equivalent <strong>circuits</strong> used to generate them were<br />

presented in Chapter 2. As one extreme for comparing the HBM withst<strong>and</strong> voltage,<br />

VHBM,ws , to ITLP,ws , we assume that some total energy is required to create device failure,<br />

independent <strong>of</strong> waveform. This assumes adiabatic thermal boundary conditions, i.e., a hot<br />

spot leading to second breakdown which occurs in the device before any generated heat<br />

diffuses from the region <strong>of</strong> heating. In this case, the energy required for failure is<br />

(5.42)<br />

where I(t) is the stress current <strong>and</strong> RDUT is the resistance <strong>of</strong> the device under test. For a<br />

TLP stress, the current is constant for the duration <strong>of</strong> the pulse, so<br />

where t TLP is the width <strong>of</strong> the pulse.<br />

∞<br />

∫<br />

Efail I 2 = ()R t DUTdt TLP<br />

Efail 0<br />

2<br />

= ITLPRDUTtTLP In the case <strong>of</strong> the ideal HBM pulse, if we assume that R DUT

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