CAPÍTULO UNO

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TRADICIÓN E INNOVACIÓN S.A. de C.V. Balance global de masa: Mp=1023 Kg/h Mf = Mp + Mv − − − − − − − − − − − − − ( 1) MfXf De la ecuación 1 despejamos Mv Calculo de cp: = MpXp − − − − − − − − − − − − − − − ( 2) Mv = Mf − Mp Mv = 0Kg / h [ ( 100 % agua) ] ⎛ % agua ⎞ ⎡⎛ − cp = ⎜ ⎟ + 0. 2 100 ⎢⎜ ⎝ ⎠ ⎣⎝ 100 % de agua en el producto a la entrada:86 Para calcular calor: Cp (kcal/kgºC) Cp=0.888 305 ⎞⎤ ⎟⎥ ⎠⎦ Q = Msλs Q = UA( Ts − Tb) Q = MfCp( Tb − Tf ) + Mvλv Q= 48,146 Kcal/h − − − − − − − Calculo de Ms para saber cuanta masa de vapor se requiere para evaporar Mv: Q MH 2Oe = Cp( T 2 − T1) MH2Oe=26,75Kg/h ( 3)
TRADICIÓN E INNOVACIÓN S.A. de C.V. Anexo 2 MEMORIA DE CÁLCULO PARA TANQUES: Tanque que contiene almacenado aguamiel. Datos: Diámetro= 0.94m Capacidad= 1.25m Presión de diseño= 1 atm Presión de operación= 1 atm Temperatura de diseño=5.5ºC Temperatura de operación= 5 ºC Radiografiado= 85% Spgr=1 Suponiendo un diámetro VOLUMEN DEL CILINDRO 2 lb ⎛144in ⎞ lb S = 11, 200 = 1, 612, 800 2 2 2 in ⎜ ft ⎟ ⎝ ⎠ ft 1 1ft tcorr in = 0. 125in = 0. 0104 ft 8 12in ⎛ 1 ft ⎞ D = 0 . 94m⎜ ⎟ = 3. 083 ft ⎝ 0. 3048m ⎠ ⎛ D ⎞ 3. 083 ft radio = ⎜ ⎟ = = 1. 54 ft ⎝ 2 ⎠ 2 2 V = πr h Despejando h y como dato tenemos que el V=1500L lo que equivale 1.5m 3 3 ⎛ V ⎞ 1. 25m 39. 37in h = ⎜ = = 1. 105m = 43. 51in 2 ⎟ 2 ⎝ πr ⎠ π 1m ( 0. 6m) 306
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Usos: TRADICIÓN E INNOVACIÓN S.A.
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EQUIPO TRADICIÓN E INNOVACIÓN S.A
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EQUIPO TRADICIÓN E INNOVACIÓN S.A
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CAPÍTULO UNO

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