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Handbook of Solvents - George Wypych - ChemTech - Ventech!

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1490 Victor Cherginets<br />

Thermal dependence <strong>of</strong> ZrO 2 solubility (molar fraction, N) in molten KCl-NaCl was<br />

evaluated in the temperature range <strong>of</strong> 973-1174 K: 39 N=(-5.7±3.1)×10-6 + (7±3)×10 -9 ×T.<br />

ZrO 2 solubility at t~700 o C was negligible.<br />

Barbin et al. 40,41 determined thermal dependence <strong>of</strong> Li 2O solubility in equimolar mixture<br />

KCl-NaCl by isothermal saturation technique in temperature range <strong>of</strong> 973-1073 K:<br />

N=0.107-5.221/T, in this range the solubility varied from 0.52 to 0.86 mol%. In earlier work<br />

by Kaneko and Kojima, 42 the solubility at 973 K was lower (0.31 mol%). The solubility <strong>of</strong><br />

lithium oxide was close to that for BaO.<br />

Solubility products <strong>of</strong> some oxides in molten KCl-NaCl in molarity scale are presented<br />

in Table 21.3.1 and plotted in Figure 21.3.1 (data obtained by same authors are connected<br />

by lines).<br />

Table 21.3.1. Oxide solubilities in molten KCl-NaCl at 700 o C (-log P, molarities)<br />

Oxide pP 11,28-32<br />

pP 29<br />

pP 8<br />

pP 9<br />

pP 33,38<br />

MgO 9.00±0.15 8.46 9.27±0.06<br />

CaO ~6.29 6.62 8.36 4.36±0.06<br />

SrO 3.00 5.84 7.60 3.08±0.40<br />

BaO 2.31±0.05 4.22 7.05 2.30±0.15<br />

NiO 11.2 8.32 9.03±0.06<br />

ZnO 6.18 6.93±0.20<br />

Cu2O 5.4 4.17±0.30<br />

MnO 6.78±0.05<br />

CoO 7.89±0.03<br />

CdO 5.00±0.03<br />

PbO 5.12±0.05<br />

Two groups <strong>of</strong> values are presented: obtained from isothermal saturation and<br />

potentiometric results. The precision <strong>of</strong> results from isothermal saturation is worse. The<br />

potentiometric results should give lower values than isothermal saturation because it includes<br />

molecular oxide concentration. Figure 21.3.1 shows that results have opposite trend<br />

to [21.3.10].<br />

The following explanation <strong>of</strong> the above discrepancy is proposed. 43,44 Let us consider<br />

the chemical potential, μ, <strong>of</strong> oxide in its saturated solution:<br />

0<br />

μ = μ + RT lns<br />

MeO, s MeO, l MeO, l<br />

[21.3.14]<br />

From this equation it follows that the oxide solubility should be constant. But every<br />

precipitate possesses a definite surface, hence, the effect <strong>of</strong> latter should be taken into account,<br />

too:<br />

where:<br />

0<br />

μ + σS = μ + RTlns MeO, s MeO, l MeO, l<br />

σ the surface energy<br />

S molar surface square <strong>of</strong> the precipitate<br />

[21.3.15]

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