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Handbook of Solvents - George Wypych - ChemTech - Ventech!

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538 Y. Y. Fialkov, V. L. Chumak<br />

Possibility <strong>of</strong> management <strong>of</strong> the products` output may by illustrated by the data from<br />

reaction equilibrium [9.84]. As follows from Figure 9.8, maximum equilibrium constant (in<br />

investigated solvents) is for pure chloroheptane; the adducts output in this solvent equals to<br />

86% (at initial concentration <strong>of</strong> reagent 0.1 M). Minimum equilibrium constant <strong>of</strong> the process<br />

is in pure ethyl acetate, where the products` output equals to 18 % (at initial concentration<br />

<strong>of</strong> reagent 0.1 M). Thus the products` output <strong>of</strong> the reaction [9.84] can be changed<br />

directionally in the range 90 up to 20% by means <strong>of</strong> choice <strong>of</strong> corresponding binary or individual<br />

solvent. If selected solvent is more basic than ethyl acetate or more acidic than<br />

nitromethane, the process is not possible.<br />

Heteromolecular association process <strong>of</strong> o-nitrophenol and triethylamine can be an example<br />

<strong>of</strong> the management <strong>of</strong> products` output. Association constant <strong>of</strong> this process has been<br />

determined for some solvents. 35 Use <strong>of</strong> hexane instead <strong>of</strong> 1,2-dichloroethane, DHLE, increases<br />

products’ output from 6% to 93%.<br />

When both components <strong>of</strong> the mixed solvent are solvate-active towards the reagents<br />

<strong>of</strong> equilibrium [9.64], the following interactions take place:<br />

E + A ↔ EA; F + A ↔ FA; E + B ↔ EB; F + B ↔FB<br />

[9.87]<br />

The process <strong>of</strong> heteromolecular association [9.64] is due to displacement <strong>of</strong> the solvent<br />

components and formation <strong>of</strong> completely or partially desolvated adduct:<br />

( ) () ()<br />

xEA + yFA + m −xEB ↔ E F + A + B<br />

[9.88]<br />

m n<br />

It is easy to develop the equation for binary solvent formed from two solvate-active<br />

components similar to [9.90] by using the above scheme for the binary solvent with one<br />

solvate active component (equations [9.76 - 9.80]) and introducing equilibrium constant <strong>of</strong><br />

the process [9.88] such as K us:<br />

( )( )( )( )<br />

K = K 1+ K 1+ K 1+ K 1 + K<br />

[9.89]<br />

EF us EA FA EB FB<br />

where:<br />

Ki equilibrium constant <strong>of</strong> the processes [9.87]<br />

9.4.4.1 Selective solvation. Resolvation<br />

When component B is added to solution E in solvent A (E is neutral molecule or ion),<br />

resolvation process takes place:<br />

EAP + qB = EB q + pA<br />

[9.90]<br />

Equilibrium constant <strong>of</strong> this process in ideal solution (in molar parts <strong>of</strong> the components)<br />

equals to:<br />

p<br />

q<br />

K = m m / m m<br />

[9.91]<br />

us EBq A EAp B<br />

where:<br />

mi a number <strong>of</strong> moles<br />

p, q stoichiometric coefficients <strong>of</strong> reaction<br />

On the other hand, resolvation constant Kus equals to the ratio <strong>of</strong> equilibrium constants <strong>of</strong><br />

solvation processes E+pA↔EAp(I);E+qB↔EBq(II):

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