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Handbook of Solvents - George Wypych - ChemTech - Ventech!

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9.3 Physical properties <strong>of</strong> mixed solvents 511<br />

base acid<br />

Et 3N + PhNH 2 ↔ Et 3N⋅PhNH 2<br />

PhNH 2 + Ph 2NH ↔ PhNH 2⋅Ph 2NH<br />

Ph 2NH + H 2O ↔ Ph 2NH⋅H 2O<br />

H2O + HAc ↔�↔ H3O + +Ac -<br />

HAc + CF3COOH ↔�↔ H2Ac + +CF3COO -<br />

CF 3COOH + HNO 3 ↔ CF 3COOH⋅HNO �<br />

+ -<br />

HNO3 + H2SO4 ↔ H2NO3+HSO4* + -<br />

H2SO4 + CF3SO3H ↔ H3SO4 +CF3SO3 *The first stage <strong>of</strong> absolute sulfuric and nitric acids<br />

9.3 PHYSICAL PROPERTIES OF MIXED SOLVENTS<br />

9.3.1 THE METHODS OF EXPRESSION OF MIXED SOLVENT<br />

COMPOSITIONS<br />

In the practice <strong>of</strong> study and application <strong>of</strong> mixed solvents the fractional (percentage)<br />

method <strong>of</strong> composition expression, according to which the fraction, Y, or percentage,<br />

Y*100, <strong>of</strong> i-component in mixed solvent are equal, is the most common:<br />

i i<br />

i= i<br />

∑<br />

i=<br />

1<br />

i<br />

Y = c / c<br />

[9.14]<br />

i i<br />

Yi = ci ci<br />

i<br />

⎛ = ⎞<br />

⎜ / ∑ ⎟× 100 %<br />

[9.14a]<br />

⎝ = 1 ⎠<br />

where:<br />

c a method <strong>of</strong> composition expression.<br />

The volume fraction, V, <strong>of</strong> a given component in the mixture equals to:<br />

i i<br />

i= i<br />

∑<br />

i=<br />

1<br />

i<br />

V = v / v<br />

where:<br />

v initial volume <strong>of</strong> component<br />

Molar fraction, X, equals<br />

i<br />

i= i<br />

∑<br />

i=<br />

1<br />

i<br />

X = m / m<br />

[9.15]<br />

[9.16]

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