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Óptica Moderna Fundamentos e aplicações - Fotonica.ifsc.usp.br ...

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150<<strong>br</strong> />

γ<<strong>br</strong> />

12<<strong>br</strong> />

() τ<<strong>br</strong> />

e portanto,<<strong>br</strong> />

< E 0exp<<strong>br</strong> />

=<<strong>br</strong> />

12<<strong>br</strong> />

{ i[<<strong>br</strong> />

−ωt<<strong>br</strong> />

+ φ(<<strong>br</strong> />

t)<<strong>br</strong> />

] } E exp{<<strong>br</strong> />

− i[<<strong>br</strong> />

−ω(<<strong>br</strong> />

t + τ)<<strong>br</strong> />

+ φ(<<strong>br</strong> />

t + τ)<<strong>br</strong> />

] }<<strong>br</strong> />

0<<strong>br</strong> />

*<<strong>br</strong> />

1 1<<strong>br</strong> />

< E E<<strong>br</strong> />

> <<<strong>br</strong> />

2<<strong>br</strong> />

2 () τ = exp{ iωτ}<<strong>br</strong> />

E 0 exp{<<strong>br</strong> />

i[<<strong>br</strong> />

φ(<<strong>br</strong> />

t)<<strong>br</strong> />

− φ(<<strong>br</strong> />

t + τ)<<strong>br</strong> />

] } / E 0<<strong>br</strong> />

E<<strong>br</strong> />

2<<strong>br</strong> />

E<<strong>br</strong> />

* 2<<strong>br</strong> />

><<strong>br</strong> />

Coerência<<strong>br</strong> />

><<strong>br</strong> />

(7.11)<<strong>br</strong> />

γ (7.12)<<strong>br</strong> />

Escrevendo a média temporal de forma explícita obtemos:<<strong>br</strong> />

1 T<<strong>br</strong> />

γ12 () τ = exp{<<strong>br</strong> />

iωτ}<<strong>br</strong> />

lim exp{<<strong>br</strong> />

i[<<strong>br</strong> />

φ()<<strong>br</strong> />

t − φ(<<strong>br</strong> />

t + τ)<<strong>br</strong> />

}dt<<strong>br</strong> />

T T ∫<<strong>br</strong> />

] (7.13)<<strong>br</strong> />

→∞<<strong>br</strong> />

0<<strong>br</strong> />

Para resolver esta integral devemos considerar dois casos: τ0 > τ e<<strong>br</strong> />

τ0 < τ, que serão analisados a seguir.<<strong>br</strong> />

Caso a) τ 0 > τ<<strong>br</strong> />

A Fig. 7.3 mostra como Δφ(t) = φ(t) - φ(t +τ) varia com o tempo.<<strong>br</strong> />

Para n τ 0 < t < (n+1) τ 0 - τ temos Δ φ = 0 e para (n + 1) τ 0 - τ < t <<<strong>br</strong> />

(n+1) τ 0 , temos Δ φ = Δ n+1. Logo, realizando explicitamente a integral<<strong>br</strong> />

temos:<<strong>br</strong> />

∫<<strong>br</strong> />

0<<strong>br</strong> />

T<<strong>br</strong> />

exp<<strong>br</strong> />

∞<<strong>br</strong> />

2π<<strong>br</strong> />

[ i Δφ()<<strong>br</strong> />

t ]<<strong>br</strong> />

π<<strong>br</strong> />

0<<strong>br</strong> />

dt<<strong>br</strong> />

0<<strong>br</strong> />

Δφ(t) nτ0 t t+τ (n+1)τ0<<strong>br</strong> />

Δ1 Δ2<<strong>br</strong> />

Δ3<<strong>br</strong> />

τ0<<strong>br</strong> />

τ0 2τ0 3τ0<<strong>br</strong> />

τ0-τ 2τ0-τ 3τ0-τ<<strong>br</strong> />

Fig. 7.3 - Variação de Δφ com o tempo.<<strong>br</strong> />

∞ ( n+<<strong>br</strong> />

1)<<strong>br</strong> />

τ0<<strong>br</strong> />

−τ<<strong>br</strong> />

( n+<<strong>br</strong> />

1)<<strong>br</strong> />

τ0<<strong>br</strong> />

= ∑ { ∫ e xp(<<strong>br</strong> />

i0)<<strong>br</strong> />

dt + ∫ exp(<<strong>br</strong> />

i Δ n+<<strong>br</strong> />

1 ) dt }<<strong>br</strong> />

nτ<<strong>br</strong> />

( n+<<strong>br</strong> />

1)<<strong>br</strong> />

τ −τ<<strong>br</strong> />

n=<<strong>br</strong> />

0<<strong>br</strong> />

0<<strong>br</strong> />

∞<<strong>br</strong> />

[ ( n + 1)<<strong>br</strong> />

τ − τ − nτ<<strong>br</strong> />

] + exp[<<strong>br</strong> />

iΔ<<strong>br</strong> />

] [ ( n + 1)<<strong>br</strong> />

τ − ( n + 1)<<strong>br</strong> />

τ + τ]<<strong>br</strong> />

= ∑<<strong>br</strong> />

0<<strong>br</strong> />

0 ∑<<strong>br</strong> />

n=<<strong>br</strong> />

0<<strong>br</strong> />

∞<<strong>br</strong> />

n=<<strong>br</strong> />

0<<strong>br</strong> />

∞<<strong>br</strong> />

n+<<strong>br</strong> />

1<<strong>br</strong> />

( τ − τ)<<strong>br</strong> />

+ τ exp(<<strong>br</strong> />

i Δ ) = n(<<strong>br</strong> />

τ − τ)<<strong>br</strong> />

= ∑ 0 ∑<<strong>br</strong> />

n=<<strong>br</strong> />

0<<strong>br</strong> />

n=<<strong>br</strong> />

0<<strong>br</strong> />

n+<<strong>br</strong> />

1<<strong>br</strong> />

0<<strong>br</strong> />

0<<strong>br</strong> />

0<<strong>br</strong> />

t<<strong>br</strong> />

0<<strong>br</strong> />

(7.14)<<strong>br</strong> />

S. C. Zilio <strong>Óptica</strong> <strong>Moderna</strong> – <strong>Fundamentos</strong> e Aplicações

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