06.02.2024 Views

Um Curso de Calculo - Vol

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f(–π/2, π/2) = 1.

A convergência não é uniforme em [–π/2, π/2], pois as funções f n são contínuas em [–π/2, π/2],

porém seu limite f é descontínuo em ±π/2, contrariando o teorema 1.

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