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statistique, théorie et gestion de portefeuille - Docs at ISFA

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9.1. Les différentes mesures <strong>de</strong> dépendances extrêmes 267<br />

which finally yields<br />

m20 = u 2 (1 + ρ)2 1<br />

+ 2 (1 + ρ) − 2 ·<br />

1 − ρ u2 + 2(5 + 4ρ + ρ3 )(1 + ρ) 2<br />

(1 − ρ) 2<br />

<br />

1 1<br />

+ O<br />

u4 u6 <br />

. (A.32)<br />

A.2.4 Asymptotic behavior of the cross moment m11<br />

The cross moment m11 = E[X · Y | X > u, Y > u] is given by expression (A.15). The first and second<br />

terms in the right hand si<strong>de</strong> of (A.15) respectively give<br />

2ρ u φ(u)[1 − Φ(u)] = 2ρ<br />

1 − ρ 2<br />

√ 2π<br />

1 + ρ<br />

1 − ρ<br />

which, after factoriz<strong>at</strong>ion by (1 + ρ)/ρ, yields<br />

and finally<br />

m11 L(u, u; ρ) =<br />

(1 + ρ)2<br />

1 − ρ 2<br />

u2<br />

−<br />

e 1+ρ<br />

2π<br />

<br />

2 1 + ρ 1 1 + ρ<br />

1 − · + 3 ·<br />

1 − ρ u2 1 − ρ<br />

1<br />

u4 3 1 + ρ<br />

−15 ·<br />

1 − ρ<br />

1<br />

<br />

1<br />

+ O<br />

u6 u8 , (A.33)<br />

<br />

2<br />

φ<br />

1 + ρ u<br />

<br />

= 1 − ρ<br />

−30<br />

m11 = u 2 + 2 (1 + ρ) − (1 + ρ)2 (3 − ρ)<br />

(1 − ρ)<br />

u2<br />

−<br />

e 1+ρ<br />

2π<br />

<br />

ρ<br />

1 − 2<br />

1 − ρ<br />

ρ(1 + ρ)2 1<br />

·<br />

(1 − ρ) 3 u<br />

A.2.5 Asymptotic behavior of the correl<strong>at</strong>ion coefficient<br />

6 + O<br />

2 e− u2<br />

1+ρ<br />

2π<br />

· 1<br />

u2 + (16 − 9ρ + 3ρ2 )(1 + ρ) 3<br />

(1 − ρ) 2<br />

, (A.34)<br />

1 ρ(1 + ρ) 1<br />

· + 6 ·<br />

u2 (1 − ρ) 2 u4 <br />

1<br />

u8 <br />

+ ρ L(u, u; ρ), (A.35)<br />

· 1<br />

<br />

1<br />

+ O<br />

u4 u6 <br />

. (A.36)<br />

The conditional correl<strong>at</strong>ion coefficient conditioned on both X and Y larger than u is <strong>de</strong>fined by (A.12).<br />

Using the symm<strong>et</strong>ry b<strong>et</strong>ween X and Y , we have m10 = m01 and m20 = m02, which allows us to rewrite<br />

(A.12) as follows<br />

ρu = m11 − m10 2<br />

. (A.37)<br />

m20 − m10<br />

2<br />

Putting tog<strong>et</strong>her the previous results, we have<br />

which proves th<strong>at</strong><br />

m20 − m10 2 =<br />

m11 − m10 2 = ρ<br />

ρu = ρ<br />

(1 + ρ)2<br />

u 2<br />

(1 + ρ)3<br />

1 − ρ<br />

1 + ρ<br />

1 − ρ<br />

− 2 (4 − ρ + 3ρ2 + 3ρ3 )(1 + ρ) 2<br />

·<br />

1 − ρ<br />

1<br />

<br />

1<br />

+ O<br />

u4 u6 <br />

, (A.38)<br />

<br />

1 1<br />

· + O<br />

u4 u6 <br />

, (A.39)<br />

<br />

1 1<br />

· + O<br />

u2 u4 <br />

29<br />

and ρ ∈ [−1, 1). (A.40)

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