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statistique, théorie et gestion de portefeuille - Docs at ISFA

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9.1. Les différentes mesures <strong>de</strong> dépendances extrêmes 277<br />

∞<br />

Cν<br />

− du<br />

−∞ (1 + u2<br />

<br />

<br />

<br />

ν+1 <br />

(E.128)<br />

ν ) 2 <br />

<br />

<br />

x <br />

0<br />

ɛ 1<br />

= du<br />

1−x0 (1 +<br />

ɛ<br />

ɛu<br />

<br />

Cν<br />

− 1<br />

)ν<br />

x0 (1 + u2<br />

ν+1 −<br />

ν ) 2<br />

1−x0 ɛ Cν<br />

− du<br />

−∞ (1 + u2<br />

∞<br />

Cν<br />

ν+1 − du<br />

x<br />

ν ) 2<br />

0<br />

ɛ (1 + u2<br />

<br />

<br />

<br />

ν+1 <br />

ν ) 2 (E.129)<br />

<br />

<br />

x <br />

0<br />

ɛ 1<br />

≤ du<br />

1−x0 (1 +<br />

ɛ<br />

ɛu<br />

<br />

Cν<br />

− 1<br />

)ν<br />

x0 (1 + u2<br />

<br />

<br />

<br />

ν+1 <br />

ν ) 2 +<br />

<br />

<br />

1−x0 ɛ Cν<br />

+ du<br />

−∞ (1 + u2<br />

<br />

<br />

<br />

ν+1 <br />

ν ) 2 +<br />

<br />

<br />

∞<br />

<br />

Cν<br />

du<br />

x0 ɛ (1 + u2<br />

<br />

<br />

<br />

ν+1 <br />

ν ) 2 . (E.130)<br />

The second and third integrals obviously behave like O(ɛν ) when ɛ goes to zero since we have assumed<br />

x0<br />

→ −∞ and ɛ → ∞ when ɛ → 0. For the first integral, we have<br />

<br />

<br />

x0 ɛ<br />

<br />

<br />

<br />

1<br />

du<br />

(1 + ɛu<br />

<br />

− 1<br />

)ν<br />

x0<br />

Cν<br />

<br />

<br />

<br />

<br />

≤<br />

x0 ɛ<br />

<br />

<br />

1<br />

du <br />

(1<br />

+ ɛu<br />

<br />

<br />

<br />

− 1<br />

)ν <br />

x0<br />

Cν<br />

. (E.131)<br />

x0 > 1 wh<strong>at</strong> ensures th<strong>at</strong> 1−x0<br />

ɛ<br />

1−x 0<br />

ɛ<br />

(1 + u2<br />

ν+1<br />

ν ) 2<br />

1−x 0<br />

ɛ<br />

The function <br />

<br />

1<br />

(1 + ɛu<br />

<br />

<br />

<br />

− 1<br />

)ν <br />

x0<br />

(1 + u2<br />

ν+1<br />

ν ) 2<br />

(E.132)<br />

vanishes <strong>at</strong> u = 0, is convex for u ∈ [ 1−x0<br />

ɛ , 0] and concave for u ∈ [0, x0<br />

ɛ ] (see also figure 13), so th<strong>at</strong> there<br />

are two constants A, B > 0 such th<strong>at</strong><br />

<br />

<br />

1<br />

<br />

(1<br />

+ ɛu<br />

<br />

<br />

<br />

− 1<br />

)ν x0 ≤ −xν <br />

<br />

1<br />

<br />

(1<br />

+<br />

<br />

0 − 1<br />

1 − x0<br />

ɛ · u = −A · ɛ · u, ∀u ∈ , 0<br />

x0 − 1 ɛ<br />

(E.133)<br />

ɛu<br />

<br />

<br />

<br />

− 1<br />

)ν x0<br />

≤<br />

νɛ<br />

<br />

u = B · ɛ · u, ∀u ∈ 0,<br />

x0<br />

x0<br />

<br />

.<br />

ɛ<br />

(E.134)<br />

We can thus conclu<strong>de</strong> th<strong>at</strong><br />

<br />

<br />

x <br />

0<br />

ɛ 1<br />

du<br />

(1 + ɛu<br />

<br />

− 1<br />

)ν<br />

x0<br />

1−x 0<br />

ɛ<br />

Cν<br />

(1 + u2<br />

ν+1<br />

ν ) 2<br />

<br />

<br />

<br />

<br />

<br />

0<br />

≤ −A · ɛ<br />

1−x0 ɛ<br />

x0 ɛ<br />

+ B · ɛ du<br />

0<br />

du<br />

u · Cν<br />

(1 + u2<br />

ν+1<br />

ν ) 2<br />

u · Cν<br />

(1 + u2<br />

ν+1<br />

ν ) 2<br />

(E.135)<br />

= O(ɛ α ), (E.136)<br />

with α = min{ν, 1}. In<strong>de</strong>ed, the two integrals can be perfomed exactly, which shows th<strong>at</strong> they behave as<br />

O(1) if ν > 1 and as O(ɛν−1 ) otherwise. Thus, we finally obtain<br />

<br />

<br />

x0 ɛ 1<br />

du<br />

(1 + ɛu<br />

x0 )ν<br />

<br />

<br />

Cν <br />

− 1<br />

= O(ɛα ). (E.137)<br />

1−x 0<br />

ɛ<br />

(1 + u2<br />

ν+1<br />

ν ) 2<br />

39

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