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Thomas Calculus 13th [Solutions]

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CHAPTER 8<br />

TECHNIQUES OF INTEGRATION<br />

8.1 USING BASIC INTEGRATION FORMULAS<br />

1.<br />

2.<br />

0<br />

1<br />

16x<br />

dx<br />

2<br />

8x<br />

2<br />

2<br />

u 8x 2 du 16x dx<br />

u 2 when x 0, u 10 when x 1<br />

1 10<br />

16x<br />

1<br />

10<br />

dx du ln u<br />

2 2<br />

0 8x<br />

2 2 u<br />

x<br />

x<br />

2<br />

2<br />

ln10 ln 2 ln5<br />

dx<br />

1<br />

Use long division to write the integrand as 1<br />

x<br />

x<br />

2<br />

1<br />

dx 1 dx dx<br />

1 x 1<br />

2 2<br />

1<br />

x tan x C<br />

x<br />

1<br />

2<br />

.<br />

1<br />

3.<br />

2<br />

sec x tan x dx<br />

Expand the integrand:<br />

2 2 2<br />

sec x tan x sec x 2sec x tan x tan x<br />

2 2<br />

sec x 2sec x tan x (sec x 1)<br />

2<br />

2sec x 2sec x tan x 1<br />

2 2<br />

sec x tan x dx 2 sec x dx 2 sec x tan x dx 1 dx<br />

2 tan x 2sec x x C<br />

We have used Formulas 8 and 10 from Table 8.1.<br />

4.<br />

/3<br />

1<br />

2<br />

/4 cos x tan x<br />

dx<br />

2 1<br />

u tan x du sec x dx dx<br />

2<br />

cos x<br />

u 1 when x 4, u 3 when x / 3<br />

/3 3<br />

1 1<br />

3<br />

dx du ln u<br />

2 1<br />

/4 cos x tan x 1 u<br />

1<br />

ln 3 ln1 ln3<br />

2<br />

Copyright 2014 Pearson Education, Inc. 543

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