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Thomas Calculus 13th [Solutions]

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plot(err(x), x 1..2, title #absolute error function#);<br />

err( 1);<br />

Chapter 3 Practice Exercises 199<br />

Mathematica: (function, x1, x2, and a may vary):<br />

Clear[f , x]<br />

{x1, x2} { 1, 2};a 1;<br />

_ 3 2<br />

f[x ]: x x 2x<br />

Plot [f[x], {x, x1, x2}]<br />

lin[x _] f[a] f [a](x a)<br />

Plot[{f[x], lin[x]},{x, x1, x2}]<br />

err[x _] Abs [f[x] lin[x]]<br />

Plot[err[x], {x, x1, x2}]<br />

err//N<br />

After reviewing the error function, plot the error function and epsilon for differing values of epsilon (eps) and<br />

delta (del)<br />

eps 0.5; del 0.4<br />

Plot[{err[x], eps}, {x, a del, a del}]<br />

CHAPTER 3<br />

PRACTICE EXERCISES<br />

1.<br />

5 2<br />

0.125 0.25<br />

y x x x<br />

dy<br />

dx<br />

4<br />

5 0.25 0.25<br />

x<br />

x<br />

2.<br />

3 7<br />

3 0.7 0.3<br />

y x x<br />

dy<br />

dx<br />

2 6<br />

2.1 2.1<br />

x<br />

x<br />

3.<br />

3 2 2<br />

3( )<br />

y x x<br />

dy<br />

dx<br />

2 2<br />

3x 3(2x 0) 3x 6x 3 x( x 2)<br />

4.<br />

7<br />

7 1<br />

1<br />

y x x<br />

dy<br />

dx<br />

6<br />

7 7<br />

x<br />

5.<br />

2 2 dy<br />

( 1) ( 2 )<br />

dx<br />

2<br />

2( x 1)(2x 4x<br />

1)<br />

y x x x<br />

2 2<br />

( x 1) (2x 2) ( x 2 x)(2( x 1))<br />

2<br />

2( x 1)[( x 1) x( x 2)]<br />

6.<br />

y (2x 5)(4 x)<br />

1<br />

dy<br />

dx<br />

2 1<br />

(2x 5)( 1)(4 x) ( 1) (4 x) (2)<br />

2 2<br />

(4 x) [(2x 5) 2(4 x)] 3(4 x)<br />

7.<br />

y<br />

2 3<br />

( sec 1)<br />

dy<br />

d<br />

2 2<br />

3( sec 1) (2 sec tan )<br />

8.<br />

y<br />

1<br />

csc<br />

2 4<br />

2 2<br />

dy<br />

d<br />

2 1<br />

2<br />

csc csc cot<br />

2 4 2 2<br />

2<br />

1 csc (csc cot )<br />

2 4<br />

9.<br />

1 1<br />

s 1 t t<br />

t<br />

1 t t<br />

ds<br />

2 t 2 t<br />

1<br />

2<br />

2 2<br />

1 t dt<br />

1<br />

t<br />

2 t 1 t 2 t 1 t<br />

10. s 1<br />

t 1<br />

ds<br />

dt<br />

( t 1) (0) 1<br />

1<br />

2 t 1<br />

2 2<br />

t 1 2 t t 1<br />

11.<br />

2 2<br />

y 2 tan x sec x<br />

dy<br />

dx<br />

2 2<br />

(4 tan x)(sec x) (2sec x)(sec x tan x) 2sec x tan x<br />

Copyright<br />

2014 Pearson Education, Inc.

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