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Thomas Calculus 13th [Solutions]

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Section 9.5 Systems of Equations and Phase Planes 691<br />

dz n<br />

dx<br />

dz n<br />

dx<br />

2<br />

1<br />

zn<br />

1<br />

F x, y, z1, z2, , zn<br />

1<br />

9. In the absence of foxes b 0 dx<br />

dt<br />

number of rabbits.<br />

a x and the population of rabbits grows at a rate proportional to the<br />

dy<br />

10. In the absence of rabbits d 0 c y and the population of foxes decays (since the foxes have no<br />

dt<br />

food source) at a rate proportional to the number of foxes.<br />

11. dx<br />

0 a<br />

dy<br />

a b y x y or x 0; c d x y 0 x c or y<br />

dt<br />

b<br />

dt<br />

d<br />

0 equilibrium points at (0, 0)<br />

or c , a<br />

d b<br />

. For the point (0, 0), there are no rabbits and no foxes. It is an unstable equilibrium point, if there<br />

are no foxes, but a few rabbits are introduced, then dx<br />

dt<br />

a the rabbit population will grow exponentially<br />

away from (0, 0).<br />

12. Let x( t ) and y( t ) both be positive and suppose that they satisfy the differential equations dx ( a b y)<br />

x and<br />

dt<br />

dy<br />

y ( t) x ( t)<br />

( c d x) y . Let C( t) a ln y( t) b y( t) d x( t) c ln x( t) C ( t) a b y ( t) d x ( t)<br />

c<br />

dt<br />

y( t) x( t)<br />

a b y ( t) c d x ( t) a b c d x( t) x( t) c d a b y( t) y( t) 0<br />

y( t) x( t) y( t) x( t)<br />

Since C ( t) 0 C( t) constant.<br />

13. Consider a particular trajectory and suppose that ( x0 , y 0)<br />

is such that x c<br />

0 d<br />

and y 0 a<br />

b<br />

, then dx<br />

dt<br />

0 and<br />

dy<br />

0 the rabbit population is increasing while the fox population is decreasing, points on the trajectory are<br />

dt<br />

moving down and to the right; if x c<br />

0 d<br />

and y 0 a<br />

b<br />

, then dx<br />

dt<br />

0 dy<br />

and 0 both the rabbit and fox<br />

dt<br />

populations are increasing, points on the trajectory are moving up and to the right; if x c<br />

0 d<br />

and y 0 a<br />

b<br />

, then<br />

dx dy<br />

0 and 0 the rabbit population is decreasing while the fox population is increasing, points on the<br />

dt<br />

dt<br />

trajectory are moving up and to the left; and finally if x c<br />

0 d<br />

and y 0 a<br />

b<br />

, then dx<br />

dt<br />

0 dy<br />

and 0 both the<br />

dt<br />

rabbit and fox populations are decreasing, points on the trajectory are moving down and to the left. Thus,<br />

points travel around the trajectory in a counterclockwise direction. Note that we will follow the same trajectory<br />

if ( x0 , y 0)<br />

starts at a different point on the trajectory.<br />

14. There are three possible cases: If the rabbit population begins (before the wolf ) and ends (after the wolf ) at a<br />

value larger than the equilibrium level of x c , then the trajectory moves closer to the equilibrium and the<br />

d<br />

maximum value of the foxes is smaller. If the rabbit population begins (before the wolf ) and ends (after the<br />

wolf ) at a value smaller than the equilibrium level of x c , but greater than 0, then the trajectory moves<br />

d<br />

further from the equilibrium and the maximum value of the foxes is greater. If the rabbit population begins and<br />

ends very near the equilibrium value, then the trajectory will stay near the equilibrium value, since it is a stable<br />

equilibrium, and the fox population will remain roughly the same.<br />

Copyright<br />

2014 Pearson Education, Inc.

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