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Thomas Calculus 13th [Solutions]

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842 Chapter 11 Parametric Equations and Polar Coordinates<br />

33.<br />

2 2<br />

2 2 y x<br />

2 2<br />

2 8<br />

2 8 10; asymptotes are y<br />

x<br />

2<br />

8y 2x 16 1 c a b<br />

34.<br />

2 2<br />

2<br />

x y<br />

2 2<br />

36 64<br />

64x 36y 2304 1 c a b<br />

36 64 10; asymptotes are y<br />

4<br />

3<br />

2<br />

35. Foci: 0, 2 , Asymptotes: y x c 2 and<br />

2 2<br />

b 1 y x 1<br />

a<br />

b<br />

2 2 2 2 2<br />

1 a b c a b 2a 2 2a a 1<br />

36. Foci: ( 2, 0), Asymptotes: y 1 x c 2 and<br />

2 2<br />

4 2 2<br />

4 a a 3 a 3 b 1 x y 1<br />

3 3<br />

3<br />

2 2<br />

b 1<br />

2 2 2 2<br />

b a c a b a a 4 a<br />

a 3 3<br />

3 3<br />

37. Vertices: ( 3, 0), Asymptotes: y 4 x a 3 and<br />

3<br />

b<br />

a<br />

2<br />

4 4<br />

y<br />

b (3) 4 x 1<br />

3 3 9 16<br />

2<br />

38. Vertices: (0, 2), Asymptotes: y 1 x a 2 and<br />

2<br />

a<br />

b<br />

2 2<br />

1<br />

y<br />

b 2(2) 4 x 1<br />

2 4 16<br />

39. (a)<br />

2<br />

y 8x 4 p 8 p 2 directrix is<br />

x 2, focus is (2, 0), and vertex is (0, 0);<br />

therefore the new directrix is x 1, the new<br />

focus is (3, 2), and the new vertex is (1, 2)<br />

(b)<br />

40. (a)<br />

2<br />

x 4y 4 p 4 p 1 directrix is<br />

y 1, focus is (0, 1) and vertex is (0, 0);<br />

therefore the new directrix is y 4, the new<br />

focus is ( 1, 2), and the new vertex is ( 1, 3)<br />

(b)<br />

41. (a)<br />

2<br />

x 2 y<br />

1<br />

16 9<br />

center is (0, 0), vertices are<br />

2 2<br />

( 4, 0) and (4, 0); c a b 7 foci<br />

are 7, 0 and 7, 0 ; therefore the new<br />

center is (4, 3), the new vertices are (0, 3) and<br />

(8, 3), and the new foci are 4 7, 3<br />

(b)<br />

Copyright<br />

2014 Pearson Education, Inc.

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