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Thomas Calculus 13th [Solutions]

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Section 9.5 Systems of Equations and Phase Planes 689<br />

6. For a fixed price, as Q increases, dp gets smaller and, possibly, becomes negative. This observation implies<br />

dt<br />

that as the quantity supplied increases, the price will not rise as fast. If Q gets high enough, then the price will<br />

dQ<br />

decrease. Next, consider : For a fixed quantity, as P increases, dQ gets larger. Thus, as the market price<br />

dt<br />

dt<br />

increases, the quantity supplied will increase at a faster rate. If P is too small, dQ will be negative and the<br />

dt<br />

quantity supplied will decrease. This observation is the traditional explanation of the effect of market price<br />

levels on the quantity supplied.<br />

(a) dP dQ<br />

0 and 0 gives the equilibrium points ( P, Q ): (0, 0) and (25.8, 775). Now dP 0 when<br />

dt dt<br />

dt<br />

PQ 20,000 and P 0; dP<br />

dQ<br />

Q<br />

dQ<br />

0 otherwise. 0 when P and Q 0; 0 otherwise.<br />

dt<br />

dt<br />

30<br />

dt<br />

(b) These considerations give the following graphical analysis:<br />

Region<br />

dP<br />

dt<br />

dQ<br />

dt<br />

I 0 0<br />

II 0 0<br />

III 0 0<br />

IV 0 0<br />

The equilibrium point (0, 0) is unstable. The graphical analysis for the point (25.8, 775) is inconclusive:<br />

trajectories near the point may be periodic, or may spiral toward or away from the point.<br />

(c) The curve dP<br />

dQ<br />

0 or PQ 20000 can be thought of as the demand curve;<br />

dt<br />

dt<br />

0 or Q 30P can be<br />

viewed as the supply curve.<br />

7. (a) dx a x b x y ( a b y)<br />

x and<br />

dt<br />

(b)<br />

dy dy dy dy ( m nx)<br />

y<br />

m y nx y ( m nx)<br />

y<br />

dx<br />

dt dt dx dt dx dx ( a b y)<br />

x<br />

dy ( m n x)<br />

y a b dy m n dx a b dy m n dx a ln y b y m ln x nx C<br />

dx ( a b y)<br />

x y x y x<br />

a b y m nx C a b y m nx C a b y m n x C<br />

ln y ln e ln x ln e ln e ln y e ln x e e y e x e e ,<br />

dy<br />

dt<br />

dt<br />

(c)<br />

C a b y m n x<br />

let K e y e Kx e<br />

a b y a 1 b y a b y a 1 b y<br />

f ( y) y e f ( y) a y e b y e y e ( a b y ) and f ( y) 0 y 0 or y a ;<br />

b<br />

f a a<br />

a 1<br />

a<br />

0 ( )<br />

b<br />

b b<br />

e f y has a unique max of a<br />

M a when a<br />

y y<br />

eb b<br />

.<br />

m nx m 1 n x m nx m 1 n x<br />

g( x) x e g ( x) mx e nx e x e ( m nx ) and g ( x) 0 x 0 or x m ;<br />

n<br />

g m m<br />

m 1<br />

m<br />

0 ( )<br />

n<br />

n n<br />

e g x has a unique max of m<br />

m<br />

M x when x m<br />

en<br />

n<br />

Copyright<br />

2014 Pearson Education, Inc.

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