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Thomas Calculus 13th [Solutions]

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1166 Chapter 16 Integrals and Vector Fields<br />

F<br />

2 2 2 2<br />

1 2 n i j F<br />

0 0<br />

1 n<br />

Circ 0 dt 0 and Circ dt 2 ; (cos t) (sin t) cos t sin t 1 and<br />

2 n<br />

1<br />

2 2<br />

dt<br />

0<br />

2<br />

0<br />

d r<br />

dt<br />

0 Flux 2 and Flux 0 dt 0<br />

(b) r (cos t) i (4 sin t) j, 0 t 2 ( sin t) i (4 cos t) j, F1<br />

(cos t) i (4 sin t) j , and<br />

dr<br />

dr<br />

2 1 dt<br />

2 dt<br />

1<br />

F ( 4 sin t ) i (cos t ) j F 15 sin t cos t and F 4 Circ 15 sin t cos t dt<br />

2<br />

15 2<br />

2<br />

sin t 0 and Circ<br />

4 1<br />

2 2 4 dt 8 ; n cos t i sin t j F<br />

0 17 17<br />

1 n<br />

0<br />

4 2 4 2 15<br />

2 2<br />

F<br />

4<br />

2 n 1 F<br />

17 17 17 0<br />

1 n v<br />

0 17<br />

cos t sin t and sin t cos t Flux | | dt 17 dt<br />

2 2 2<br />

2<br />

15 15<br />

2 F<br />

0<br />

2 n v dt t t dt t<br />

0 17 2 0<br />

8 and Flux | | sin cos 17 sin 0<br />

2<br />

0<br />

30. r ( a cos t) i ( a sin t) j, 0 t 2 , F1 2xi 3 yj, and F2<br />

2 xi ( x y) j ( a sin t) i ( a cos t) j,<br />

F (2a cos t) i (3a sin t) j, and F (2a cos t) i ( a cos t a sin t) j n | v| ( a cos t) i ( a sin t) j,<br />

1 2<br />

1 | |<br />

2 2<br />

2a cos t<br />

2 2<br />

3a sin t, and 2 | |<br />

2 2<br />

2a cos t<br />

2<br />

a sin t cos t<br />

2 2<br />

a sin t<br />

1<br />

2 sin 2<br />

2<br />

sin 2<br />

2<br />

2 2 2 2 2 t 2 t<br />

a t a t dt a<br />

t<br />

a<br />

t<br />

0 2 4<br />

0<br />

2 4<br />

0<br />

2<br />

a<br />

F n v F n v<br />

Flux 2 cos 3 sin 2 3 , and<br />

2<br />

2 2 2 2 2 2<br />

0<br />

2 t sin 2t<br />

2 2<br />

a 2<br />

2<br />

2 t sin 2t<br />

2<br />

2<br />

2 4<br />

0<br />

2 0 2 4<br />

0<br />

Flux 2a cos t a sin t cos t a sin t dt<br />

2a sin t a a<br />

d r<br />

dt<br />

dr<br />

dr<br />

1 dt<br />

1 dt<br />

1 1<br />

1 1<br />

31. F ( a cos t ) i ( a sin t ) j, ( a sin t ) i ( a cos t ) j F 0 Circ 0; M a cos t ,<br />

1 1<br />

C<br />

1 1<br />

0<br />

2 2 2 2<br />

N a sin t, dx a sin t dt, dy a cos t dt Flux M dy N dx a cos t a sin t dt<br />

0<br />

2 2<br />

a dt<br />

a<br />

;<br />

dr<br />

dr<br />

a<br />

2 dt 2 dt 2<br />

a<br />

2 2<br />

F ti i F t t dt M t N dx dt dy<br />

2 2<br />

, Circ 0; , 0, , 0<br />

Flux M dy N dx 0 dt 0;<br />

2<br />

C<br />

2 2<br />

therefore, Circ Circ1 Circ2<br />

0 and<br />

a<br />

a<br />

Flux Flux Flux a<br />

1 2<br />

2 2 2 2 dr<br />

dr<br />

1 1<br />

3 2 3 2<br />

dt<br />

dt<br />

1 1<br />

32. F a cos t i a sin t j, ( a sin t ) i ( a cos t ) j F a sin t cos t a cos t sin t<br />

3 2 3 2 2a<br />

2 2 2 2<br />

1<br />

0<br />

3 1 1<br />

Circ a sin t cos t a cos t sin t dt ; M a cos t , N a sin t , dy a cos t dt ,<br />

3 3 3 3 4 3<br />

1<br />

C<br />

1 1<br />

0<br />

3<br />

dx a sin t dt Flux M dy N dx a cos t a sin t dt a ;<br />

2 dr<br />

dr<br />

2 a 2 a 2<br />

2 dt 2 dt 2<br />

a 3 2 2<br />

3<br />

2 2<br />

, Circ<br />

2<br />

; , 0, 0,<br />

F t i i F t t dt M t N dy dx dt<br />

4<br />

2<br />

C<br />

2 2 1 2 1 2 3<br />

Flux M dy N dx 0; therefore, Circ Circ Circ 0 and Flux Flux Flux a<br />

3<br />

2<br />

3<br />

Copyright<br />

2014 Pearson Education, Inc.

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