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Thomas Calculus 13th [Solutions]

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Section 4.1 Extreme Values of Functions 221<br />

22. f ( x) x 4 f ( x ) 1 no critical points;<br />

f ( 4) 0, f (1) 5 the absolute maximum is 0<br />

at x 4 and the absolute minimum is 5 at x 1<br />

23.<br />

2<br />

f ( x) x 1 f ( x) 2x a critical point at<br />

x 0; f ( 1) 0, f (0) 1, f (2) 3 the absolute<br />

maximum is 3 at x 2 and the absolute minimum is<br />

1 at x 0<br />

24.<br />

f ( x) 4<br />

x<br />

3<br />

2<br />

f ( x) 3x a critical point at<br />

x 0; f ( 2) 12, f (0) 4, f (1) 3 the absolute<br />

maximum is 12 at x 2 and the absolute<br />

minimum is 3 at x 1<br />

( 2, 12)<br />

f ( x)<br />

4 x<br />

3<br />

y<br />

10<br />

5<br />

( 1, 3)<br />

2 1 0 1<br />

x<br />

1 2 3 2<br />

25. F ( x ) x F ( x ) 2 x , however<br />

2 3<br />

x<br />

x<br />

x 0 is not a critical point since 0 is not in the domain;<br />

F(0.5) 4, F (2) 0.25 the absolute maximum<br />

is 0.25 at x 2 and the absolute minimum is 4 at<br />

x 0.5<br />

1 1 2 1<br />

26. F ( x ) ( ) ,<br />

x<br />

x F x x however<br />

2<br />

x<br />

x 0 is not a critical point since 0 is not in the<br />

domain; F( 2)<br />

1<br />

, F ( 1) 1 the absolute<br />

2<br />

maximum is 1 at x 1 and the absolute minimum<br />

is 1 2 at x 2<br />

Copyright<br />

2014 Pearson Education, Inc.

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