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Thomas Calculus 13th [Solutions]

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594 Chapter 8 Techniques of Integration<br />

3 1 1<br />

3 3<br />

57. A tan x dx x tan x x dx<br />

0 0<br />

2<br />

0 1 x<br />

3<br />

3 1 2<br />

3<br />

ln x 1 ln 2;<br />

3 2<br />

0<br />

3<br />

3 1 2 1<br />

3 3 2<br />

x 1 x tan x dx 1 1 x tan x 1 x dx<br />

A 0 A 2 2 0<br />

2<br />

0 1 x<br />

3<br />

1 1 1 1 3 1 2 3<br />

x tan x<br />

1.10<br />

A 2 2<br />

0<br />

A 2 2 6 A 3 2<br />

58.<br />

5 2<br />

5 5 5 5<br />

A 4x 13x 9 125<br />

3 dx 3 dx dx 2 dx 3ln ln 3 2ln 1 ln ;<br />

3 2<br />

x 2x 3x<br />

3 x 3 x 3 3 x 1 x x x 3 9<br />

2<br />

5 x 4x 13x<br />

9<br />

1 1 5 5 5<br />

x dx 4x<br />

3 dx 2 dx 1 (8 11ln 2 3ln 6) 3.90<br />

A 3<br />

3 2<br />

x 2x 3x<br />

A 3 3 x 3 3 x 1 A<br />

59. (a) dx kx( N x) dx k dt 1 dx 1 dx k dt 1 ln x kt C;<br />

dt x( N x)<br />

N x N N x N N x<br />

(b)<br />

k 1<br />

250 , N 1000, t 0 and x 2 1 ln 2 C 1 ln x t 1 ln 1<br />

1000 998 1000 1000 x 250 1000 499<br />

4 4 4 4<br />

ln 499x 499 t t t t<br />

4t x e 499 x e (1000 x) 499 e x 1000e x 1000e<br />

1000 x 1000 x 4t<br />

499 e<br />

4t<br />

1 1000<br />

4t 4t 4t<br />

x N 500 500 e 500 499 500e 1000e e 499 t 1 ln 499 1.55days<br />

2 4t<br />

499 e<br />

4<br />

4t<br />

60.<br />

dx k( a x)( b x)<br />

dx k dt<br />

dt<br />

( a x)( b x)<br />

(a) a b: dx k dt 1 ; 0<br />

2<br />

( a x)<br />

a x<br />

kt C t and x 0 1 C 1 kt 1<br />

a a x a<br />

1 1 a x a x a a a kt<br />

a x a akt 1 akt 1 akt 1<br />

(b) a b: dx k dt 1 dx 1 dx k dt 1 ln b x<br />

( a x)( b x)<br />

b a a x b a b x b a a x<br />

kt C;<br />

t 0 and<br />

( )<br />

1<br />

0 1<br />

b a kt<br />

ab e<br />

x ln b C ln b x ( b a) kt ln b b x b e x<br />

b a a a x a a x a a be<br />

2<br />

( b a)<br />

kt<br />

( b a)<br />

kt<br />

8.6 INTEGRAL TABLES AND COMPUTER ALGEBRA SYSTEMS<br />

1.<br />

dx 2 tan 1 x 3 C<br />

x x 3 3 3<br />

(We used FORMULA 13(a) with a 1, b 3)<br />

2.<br />

dx 1 x 4 4 1 x 4 2<br />

ln<br />

C ln C<br />

x x 4 4 x 4 4 2 x 4 2<br />

(We used FORMULA 13(b) with a 1, b 4 )<br />

Copyright<br />

2014 Pearson Education, Inc.

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