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Thomas Calculus 13th [Solutions]

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Section 15.4 Double Integrals in Polar Form 1107<br />

1 3y<br />

24.<br />

2<br />

1/2 1<br />

0<br />

3/2<br />

y<br />

x dx dy or<br />

1 3 1<br />

2 x dy dx<br />

x dy dx<br />

1 x<br />

3/2 x/ 3<br />

25.<br />

2 x y<br />

2 x<br />

2 y<br />

2 dy dx or<br />

0 0<br />

2 2<br />

y 2<br />

x 2<br />

y 2<br />

0 y<br />

dx dy<br />

26.<br />

3 4 2 2<br />

3<br />

0 0 x y dy dx or 4 3 2 2<br />

3<br />

x y dx dy<br />

0 0<br />

27.<br />

/2 2 2 sin 2 /2<br />

r dr d<br />

0 0 0<br />

2 (2 sin 2 ) d 2( 1)<br />

28.<br />

/2 1 cos /2 2<br />

A 2 r dr d 2cos cos d 8<br />

0 1 0<br />

4<br />

29.<br />

/6 12cos3 /6 2<br />

A r dr d d<br />

0 0 0<br />

2 144 cos 3 12<br />

30.<br />

2 4 /3<br />

8<br />

2 2<br />

A r dr d d 64<br />

0 0 9 0<br />

27<br />

3<br />

31.<br />

/2 1 sin /2<br />

A r dr d 1 3 cos 2 d 3<br />

0 0 2 0 2 2 8<br />

2sin 1<br />

32.<br />

/2 1 cos /2<br />

A r dr d 3 cos 2 d 3<br />

0 0 0 2 2 2<br />

4 2 2cos 4<br />

4 /2 a 2 2 4<br />

/2 3 2a<br />

a 0 0 3 a 0<br />

3<br />

33. average r a r dr d a d<br />

2 2<br />

4 /2 a 2 4<br />

/2 3 2a<br />

a 0 0 3 a 0<br />

3<br />

34. average r dr d a d<br />

2 2<br />

Copyright<br />

2014 Pearson Education, Inc.

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