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Thomas Calculus 13th [Solutions]

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902 Chapter 12 Vectors and the Geometry of Space<br />

i j k<br />

33. S(0, 0,12), P (0, 0, 0) and v 4i 2j 2k PS v 0 0 12 24i 48j 24 i 2j<br />

4 2 2<br />

d<br />

PS v<br />

24 1 4 24 5<br />

| v| 16 4 4 24<br />

5 24 2 30<br />

is the distance from S to the line<br />

i j k<br />

34. S(0, 0, 0), P (5, 5, 3) and v 3i 4j 5k PS v 5 5 3 13i 16j 5k<br />

3 4 5<br />

d<br />

PS v<br />

169 256 25 450<br />

| v| 9 16 25 50<br />

9 3<br />

is the distance from S to the line<br />

PS v<br />

35. S(2, 1, 3), P (2, 1, 3) and v 2i 6j PS v 0 d<br />

0 0 is the distance from S to the line<br />

| v| 40<br />

(i.e., the point S lies on the line)<br />

i j k<br />

36. S(2, 1, 1), P (0, 1, 0) and v 2i 2j 2k PS v 2 0 1 2i 6j 4k<br />

2 2 2<br />

d<br />

PS v<br />

4 36 16 56 14<br />

| v| 4 4 4 12 3<br />

is the distance from S to the line<br />

i j k<br />

37. S(3, 1, 4), P (4, 3, 5) and v i 2j 3k PS v 1 4 9 30i 6j 6k<br />

1 2 3<br />

d<br />

PS v<br />

900 36 36 972 486 81 6 9 42<br />

| v| 1 4 9 14 7 7 7<br />

is the distance from S to the line<br />

i j k<br />

38. S( 1, 4, 3), P (10, 3, 0) and v 4i 4k PS v 11 7 3 28i 56j 28k 28 i 2j k<br />

4 0 4<br />

d<br />

PS v<br />

28 1 4 1<br />

| v| 4 1 1<br />

7 3<br />

is the distance from S to the line<br />

39. S(2, 3, 4), x 2y 2z 13 and P (13, 0, 0) is on the plane PS 11i 3j 4k and n i 2j 2k<br />

d PS n 11 6 8 9<br />

| n| 1 4 4 9<br />

3<br />

40. S(0, 0, 0), 3x 2y 6z 6 and P (2, 0, 0) is on the plane PS 2i and n 3i 2j 6k<br />

d PS n 6 6 6<br />

| n|<br />

9 4 36 49 7<br />

Copyright<br />

2014 Pearson Education, Inc.

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