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Thomas Calculus 13th [Solutions]

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270 Chapter 4 Applications of Derivatives<br />

82. The graph of y f ( x) y | the graph of<br />

y f ( x ) has a point of inflection, the graph of<br />

y f ( x) y | | the graph of y f ( x ) has<br />

both a local maximum and a local minimum<br />

83. The graph of y f ( x) y | |<br />

the graph of y f ( x ) has two points of inflection, the graph of<br />

y f ( x)<br />

y | the graph of y f ( x ) has a local<br />

minimum<br />

84. The graph of y f ( x) y | the graph of<br />

y f ( x ) has a point of inflection; the graph of<br />

y f ( x) y | | the graph of y f ( x ) has<br />

both a local maximum and a local minimum<br />

85.<br />

y<br />

2<br />

2x<br />

x 1<br />

2<br />

x 1<br />

Since 1 and 1 are roots of the denominator, the domain is<br />

( , 1) ( 1,1) (1, ).<br />

1 2<br />

y ; y ( x 1)<br />

2 3<br />

( x 1) ( x 1)<br />

There are no critical points. The function is decreasing on its<br />

domain. There are no inflection points. The function is concave<br />

down on ( , 1) ( 1,1) and concave up on (1, ). The<br />

numerator and denominator share a factor of x 1. Dividing out<br />

this common factor gives y 2x<br />

1<br />

x 1 ( x 1), which shows that<br />

x 1 is a vertical asymptote. Now dividing numerator and<br />

2 (1/ x)<br />

denominator by x gives y<br />

1 (1/ x) , which shows that y 2 is a<br />

horizontal asymptote. The graph will have a hole at x 1,<br />

y 2( 1) 1 3<br />

1( 1) 1 2 . The x-intercept is 1 2 .<br />

Copyright<br />

2014 Pearson Education, Inc.

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