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Thomas Calculus 13th [Solutions]

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186 Chapter 3 Derivatives<br />

65. The values of f increase over the interval [ 1, 1] because f 0, and the graph of f steepens as the values of<br />

f increase towards the ends of the interval. The graph of f is concave down to the left of the origin where<br />

f 0, and concave up to the right of the origin where f 0. There is an inflection point at x = 0 where<br />

f 0 and f has a local minimum value.<br />

66. The values of f increase throughout the interval ( , ) because f 0, and they increase most rapidly near<br />

the origin where the values of f are relatively large. The graph of f is concave up to the left of the origin<br />

where f 0, and concave down to the right of the origin where f 0. There is an inflection point at x = 0<br />

where f 0 and f has a local maximum value.<br />

3.10 RELATED RATES<br />

1.<br />

2.<br />

2<br />

A r dA 2 r dr<br />

dt dt<br />

2<br />

S 4 r dS 8 r dr<br />

dt dt<br />

dy<br />

dy<br />

3. y 5 x, dx 2 5 dx 5(2) 10<br />

dt dt dt dt<br />

dy<br />

4. 2x 3y 12, 2 2 dx dy<br />

3 0 2 dx 3( 2) 0 dx 3<br />

dt<br />

dt dt dt dt<br />

Copyright<br />

2014 Pearson Education, Inc.

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